在R中绘制频率密度直方图 [英] Draw frequency density histogram in R
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问题描述
Class宽频率。 Dist
0 <= x < 5 0.2
5 <= x < 15 0.1
15 <= x < 20 1.2
20 <= x < 30 0.4
30 <= x < 40 0.4
所以我想让X轴从0-5,5-15,15-
预先感谢!
解决方案
这个怎么样?
break <-c(0,5,15, 20,30,40)
计数<-c(0.2,0.1,1.2,0.4,0.4)
barplot(计数,
名称= sprintf([%g,%g) ,
break [-length(breaks)],breaks [-1]
),
space = 0
)
这会给你等宽的条。另一方面,如果您想获得各种宽度的条形图,请输入:
barplot(counts,diff ),
names = sprintf([%g,%g),中断[-length(breaks)],breaks [-1]),
space = 0
)
此外,这将为您提供一个普通X轴:
barplot(counts,diff(breaks),space = 0)
axis(1)
如果您想在 breaks
中的点精确地获取轴断点,请键入:
axis(1,at = breaks)
Using R, can anyone show me how to draw a simple histogram with no gaps between the bins of the following data :-
Class Width Freq. Dist
0 <= x < 5 0.2
5 <= x < 15 0.1
15 <= x < 20 1.2
20 <= x < 30 0.4
30 <= x < 40 0.4
So I want the X axis to go from 0-5,5-15,15-20,20-30 and 30-40 with the bars drawn appropriately.
Thanks in advance !
解决方案
How about this one?
breaks <- c(0,5,15,20,30,40)
counts <- c(0.2, 0.1, 1.2, 0.4, 0.4)
barplot(counts,
names=sprintf("[%g,%g)",
breaks[-length(breaks)], breaks[-1]
),
space=0
)
This will give you bars of equal widths. On the other hand, If you'd like to obtain bars of various widths, type:
barplot(counts, diff(breaks),
names=sprintf("[%g,%g)", breaks[-length(breaks)], breaks[-1]),
space=0
)
Moreover, this will give you an "ordinary" X axis:
barplot(counts, diff(breaks), space=0)
axis(1)
And if you'd like to get axis breaks exactly at points in breaks
, type:
axis(1, at=breaks)
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