Shell函数在特定时间为特定字符串定制日志文件 [英] Shell function to tail a log file for a specific string for a specific time

问题描述

我需要做以下事情来确保我的应用程序服务器是

1. 为特定字符串填写日志文件


2. 保持阻止状态，直到打印字符串为止
   
3. 然而，如果字符串未打印约20分钟，则退出并抛出异常消息，如服务器花费了20分钟如果字符串打印在日志文件中，退出循环并继续。

<有没有办法在一个while循环中包含超时？

解决方案

 ＃！/ bin / bash 
 tail -f logfile | grep'certain_word'|读-t 1200 dummy_var 
 [$？ -eq 0]&& echo'ok'|| echo'server not up'
  

这会读取任何写入日志文件的内容，搜索certain_word，如果全部回显是好的，否则在等待1200秒（20分钟）后就会报怨。

I need to the following things to make sure my application server is

1. Tail a log file for a specific string
2. Remain blocked until that string is printed
3. However if the string is not printed for about 20 mins quit and throw and exception message like "Server took more that 20 mins to be up"
4. If string is printed in the log file quit the loop and proceed.

Is there a way to include time outs in a while loop ?

解决方案

#!/bin/bash
tail -f logfile | grep 'certain_word' | read -t 1200 dummy_var
[ $? -eq 0 ]  && echo 'ok'  || echo 'server not up'

This reads anything written to logfile, searches for certain_word, echos ok if all is good, otherwise after waiting 1200 seconds (20 minutes) it complains.

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