我怎样才能让grep打印每条匹配行下面和上面的行？ [英] How can I make grep print the lines below and above each matching line?

问题描述

可能存在重复：

我必须解析一个非常大的文件，我想使用命令grep（或任何其他工具）。

I have to parse a very large file and I want to use the command grep (or any other tool).

我想搜索每个日志为单词 FAILED 添加一行，然后在每个匹配行上方和下方以及匹配行中打印行。

I want to search each log line for the word FAILED, then print the line above and below each matching line, as well as the matching line.

id : 15
Satus : SUCCESS
Message : no problem

---

---

id : 15
Satus : FAILED
Message : connection error

---

我需要打印：

---

And I need to print:

id : 15
Satus : FAILED
Message : connection error

推荐答案

grep's -A 1 选项会给你一行后; -B 1 会给你一行;和 -C 1 将两者结合在一起，为您提供前后一行。

grep's -A 1 option will give you one line after; -B 1 will give you one line before; and -C 1 combines both to give you one line both before and after.

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