Yii2在gridview中自定义sql查询 [英] Yii2 custom sql query in gridview
问题描述
我使用高级结构
我需要在视图中显示自定义的sql结果而不使用模型,因为我想显示一个sql视图。
index.php
<?= GridView :: widget ([
'dataProvider'=> $ dataProvider,
'columns'=> [
['class'=>'yii\grid\SerialColumn'],
'COD_RISORSA',
[
'label'=>Nome,
'attribute'=>'NOME',
'value'=> function ($ data){
return $ data [NOME];
}
],
'COGNOME',
['class'=>'yii \grid\ActionColumn'],
],
]); ?>
VRisorseController.php
public function actionIndex()
{
$ totalCount = Yii :: $ app-> db-> createCommand('SELECT COUNT(*)FROM v_risorse' ) - > queryScalar();
$ b $ dataProvider = new SqlDataProvider([
'sql'=>'SELECT * FROM v_risorse',
'totalCount'=> $ totalCount,
' sort'=> false,
'pagination'=> [
'pageSize'=> 10,
],
]);
return $ this-> render('index',[
'dataProvider'=> $ dataProvider,
]);
$ / code>
在以下网址:
http://localhost/advanced/frontend/web/index.php?r = vrisorse%2Findex
我有错误:
不支持 - yii \base \NotSupportedException消息格式'数字'
仅支持整数值。您必须安装PHP intl
扩展才能使用此功能。
1.在C:\xampp\htdocs\advanced\vendor\yiisoft\yii2\i18n\MessageFormatter.php
我试图评论gridview中的所有列,并且该错误似乎与 $ dataProvider
变量
有关
'COD_RISORSA','NOME','COGNOME'
是select的列。
您需要安装PHP intl extension.i,它具有相同的错误
是我的工作代码
in controller
$ count = Yii :: $ app-> db-> createCommand('
SELECT COUNT (*)FROM screen_ticket_booking_history WHERE status =:status
',[':status'=> 0]) - > queryScalar();
$ sql =SELECT A1.booking_id As Booking_id,
A1.booking_date As Booking_date,
A2.movie_name As Movie,
A3.theatre_name As Theatre,
A1.amount As Amount
FROM
screen_ticket_booking_history A1
LEFT OUTER JOIN电影A2 ON A1.movie_id = A2.id
LEFT OUTER加入剧院A3 ON A1.theatre_id = A3.id
LEFT OUTER JOIN users_backend A4 ON A3.users_backend_id = A4.id
WHERE A1.booking_date ='{$ day}'
AND A1.movie_id ='{$ movies-> id}';
//〜$ models = $ dataProvider-> getModels(); //的print_r($机型);模具();
if($ userid!='1')
{
$ sql。=AND A3.users_backend_id ='{$ userid}';
$ b $ dataProvider = new SqlDataProvider([
'sql'=> $ sql,
'totalCount'=> $ count,
]);
return $ this-> render('index',
['model'=> $ model,
'dataProvider'=> $ dataProvider,
]);
}
以下是我的看法
<?= GridView :: widget([
'dataProvider'=> $ dataProvider,
'columns'=> [
''class'=>'yii'grid \\'SerialColumn'],
'Booking_id',
'Booking_date',
'Movie',
'剧院',
'金额',
//〜['class'=>'yii\grid\ActionColumn'],
],
]) ; ?>
I'm quite new to Yii2. I'm using advanced structure
I need to show a custom sql result in a view without using a model because I would like to display a sql view.
index.php
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'COD_RISORSA',
[
'label' =>"Nome",
'attribute' => 'NOME',
'value'=>function($data){
return $data["NOME"];
}
],
'COGNOME',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
VRisorseController.php
public function actionIndex()
{
$totalCount = Yii::$app->db->createCommand('SELECT COUNT(*) FROM v_risorse')->queryScalar();
$dataProvider = new SqlDataProvider([
'sql' => 'SELECT * FROM v_risorse',
'totalCount' => $totalCount,
'sort' =>false,
'pagination' => [
'pageSize' => 10,
],
]);
return $this->render('index', [
'dataProvider' => $dataProvider,
]);
}
At the following Url: http://localhost/advanced/frontend/web/index.php?r=vrisorse%2Findex
I have the error:
Not Supported – yii\base\NotSupportedException Message format 'number' is only supported for integer values. You have to install PHP intl extension to use this feature. 1. in C:\xampp\htdocs\advanced\vendor\yiisoft\yii2\i18n\MessageFormatter.php
I tried to comment all the columns in gridview, and the error seems to be related to $dataProvider
variable
'COD_RISORSA','NOME', 'COGNOME'
are columns of the select.
You need to install PHP intl extension.i had the same error
given below is my working code in controller
$count = Yii::$app->db->createCommand('
SELECT COUNT(*) FROM screen_ticket_booking_history WHERE status=:status
', [':status' => 0])->queryScalar();
$sql = "SELECT A1.booking_id As Booking_id,
A1.booking_date As Booking_date,
A2.movie_name As Movie,
A3.theatre_name As Theatre,
A1.amount As Amount
FROM
screen_ticket_booking_history A1
LEFT OUTER JOIN movies A2 ON A1.movie_id=A2.id
LEFT OUTER JOIN theatres A3 ON A1.theatre_id=A3.id
LEFT OUTER JOIN users_backend A4 ON A3.users_backend_id=A4.id
WHERE A1.booking_date = '{$day}'
AND A1.movie_id='{$movies->id}'";
//~ $models = $dataProvider->getModels(); //print_r($models);die();
if( $userid != '1')
{
$sql .= " AND A3.users_backend_id = '{$userid}' ";
}
$dataProvider = new SqlDataProvider([
'sql' => $sql,
'totalCount' => $count,
]);
return $this->render('index',
[ 'model' => $model,
'dataProvider' => $dataProvider,
]);
}
and below is my view
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'Booking_id',
'Booking_date',
'Movie',
'Theatre',
'Amount',
//~ ['class' => 'yii\grid\ActionColumn'],
],
]); ?>
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