自定义列表排序 [英] Custom List sorting

问题描述

您好，我有一个包含 [每日，每月，每周] 或 [每月，每周，每日]元素的列表或 [每周，每天]

我需要以这种方式对列表进行排序

  [每日，每月，每周] == [每日，每月，每周] 
 
 [每日] == [每日，每月，每周] 
 
 [每周，每日] == [每日，每周] 
  

有人可以帮我解决这个问题。

  customSorter = {
 ['daily'，'monthly'，'每周'] .indexOf（it）
} 
 
 assert ['daily'，'monthly'，'weekly'] .sort（customSorter）== ['daily'，'monthly' ，'weekly'] 
 assert ['monthly'，'weekly'，'daily'] .sort（customSorter）== ['daily'，'monthly'，'weekly'] 
 assert [''每周，每日'] .sort（customSorter）== ['daily'，'weekly'] 
  

或者你可以做到这一点（以避免反复创建一个列表）

  customSorter = {a，b，order = ['daily'，'每月'，'每周']  - > 
 order.indexOf（a）< => order.indexOf（b）
} 
  

Hi I have a list which contains elements [daily,monthly,weekly] or [monthly,weekly,daily] or [weekly,daily]

I need to sort the list in such a way that

[daily,monthly,weekly] == [daily,monthly,weekly]

[monthly, weekly, daily] == [daily, monthly, weekly]

[weekly, daily] == [daily, weekly]

Can some one please help me in this

解决方案

Assuming you mean that you have a list of Strings, then this should work:

customSorter = { 
  [ 'daily', 'monthly', 'weekly' ].indexOf( it )
}

assert [ 'daily', 'monthly', 'weekly' ].sort( customSorter ) == [ 'daily', 'monthly', 'weekly' ]
assert [ 'monthly', 'weekly', 'daily' ].sort( customSorter ) == [ 'daily', 'monthly', 'weekly' ]
assert [ 'weekly', 'daily' ].sort( customSorter ) == [ 'daily', 'weekly' ]

Or you could do this (to avoid repeatedly creating a List)

customSorter = { a, b, order=['daily','monthly','weekly'] ->
  order.indexOf( a ) <=> order.indexOf( b )
}

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