Groovy脚本获取请求xml [英] Groovy script to get the request xml

问题描述

我可以使用Groovy脚本获得响应xml。我需要获取请求XML，因为我需要添加断言脚本到我的soap ui测试。

我使用以下代码来获取响应xml

p>

  def response = new XmlHolder（messageExchange.responseContentAsXml）
  

但我不确定如何获取SOAPUI的请求xml。任何人都可以请求帮助我获得SOPAUI的请求xml吗？

解决方案

要获取请求内容作为字符串，您可以使用

  testRunner.testCase.testSteps [testteup的名称]。testRequest.response.getRequestContent（）
  

有关SoapUI API的更多信息，请参阅 http://www.soapui.org/apidocs/index.html?overview-summary.html 。查看Request和Response类，特别是它们提供的方法和属性。


I can get the response xml using Groovy script. I need to get the request XML since I need to add 'assertion script' to my soap ui testing.

I am using the following code to get the response xml

def response = new XmlHolder(messageExchange.responseContentAsXml)

But I am not sure how to get the request xml of SOAPUI. Can anyone please help me in getting the request xml of SOPAUI?

解决方案

To get the request content as a string you can use

testRunner.testCase.testSteps["Name of your teststeup"].testRequest.response.getRequestContent()

More information on the SoapUI API can be found at http://www.soapui.org/apidocs/index.html?overview-summary.html. Have a look at the Request and Response class in particular for the methods and properties they provide

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