用于正则表达式匹配的Groovy语法 [英] Groovy syntax for regular expression matching

问题描述

以下Perl代码的Groovy等价物是什么？

  my $ txt =abc：groovy：def; 
 if（$ txt =〜/：（。+？）：/）{
 my $ match = $ 1; 
打印MATCH = $ match \\\
; 
＃应打印MATCH = groovy \\\

} 
  

I知道有多种方法可以做到这一点（包括常规的Java方式） - 但是做到这一点的Groovy方法是什么？

这是一种方法这样做，但它感觉有点笨拙 - 特别是数组表示法（ m [0] [1] ），这感觉有点奇怪。有没有更好的方法呢？如果不是，请描述 m [0] [1] 背后的逻辑。

 <$ c如果（（m = txt =〜/：（。+？）：/））{
 def match = m [0] [1]，$ c> def txt =java：groovy：grails ] 
 printlnMATCH = $ match
} 
  

解决方案<

  def txt =abc：
这是与我可以实现的Perl代码最接近的匹配： groovy：def
 if（（m = txt =〜/：（。+？）：/））{
 def match = m.group（1）
 printlnMATCH = $匹配

  

What is the Groovy equivalent of the following Perl code?

my $txt = "abc : groovy : def";
if ($txt =~ / : (.+?) : /) {
  my $match = $1;
  print "MATCH=$match\n"; 
  # should print "MATCH=groovy\n"
}

I know that there's more than one way to do it (including the regular Java way) - but what is the "Groovy way" of doing it?

This is one way of doing it, but it feels a bit clumsy - especially the array notation (m[0][1]) which feels a bit strange. Is there a better way do it? If not - please describe the logic behind m[0][1].

def txt = "java : groovy : grails"
if ((m = txt =~ / : (.+?) :/)) {
  def match = m[0][1]
  println "MATCH=$match"
}

解决方案

This was the closest match to the Perl code that I could achieve:

def txt = "abc : groovy : def"
if ((m = txt =~ / : (.+?) : /)) {
  def match = m.group(1)
  println "MATCH=$match"
}

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