你如何看待多个文件，但只能在Grunt.js中运行更改文件的任务？ [英] How do you watch multiple files, but only run task on changed file, in Grunt.js?

问题描述

在学习如何使用咕噜时，我正在尝试制作一个简单的咖啡脚本观察器/编译器。问题是，如果我告诉监视任务来观看几个文件，并且一个文件发生了变化，它将把所有文件传递给咖啡命令。这意味着当您更改1个文件时，它将重新编译与 src 模式匹配的所有文件。相反，我只想重新编译单个匹配 src 模式的文件。

这是 grunt.js ：

  module.exports = function（grunt）{
 grunt.initConfig（{
 coffee：{
 app：{
 src：['test / cases / controller / *。coffee']，
 dest：'tmp '，
选项：{
 bare：true，
 preserve_dirs：true 
} 
} 
}，
手表：{
文件：['< config：coffee.app.src>']，
 tasks：['coffee：app'] 
} 
}）; 
 
 grunt.loadNpmTasks（'grunt-coffee'）; 
 grunt.registerTask（'default'，'coffee'）; 
}; 
  

这是使用 grunt-coffee ，这基本上是这样的： https：//gist.github .com / 2373159 。

当我运行 grunt watch 时，我将文件保存在 test / cases / controller / *。coffee ，它编译匹配文件的所有（将它们放在 tmp / * ）。

您是如何使用grunt 编译已更改文件？

解决方案

即将发布（目前正在开发中）v0.4.0a grunt拥有 grunt.file.watchFiles 对象，该对象专为此目的而设计。 grunt-coffee插件可能已经增加了对此功能的支持，我不确定。

无论哪种方式，如果您有兴趣尝试一个开发版本咕噜在你的项目中，看看我什么时候可以使用开发中的功能'X'？ FAQ条目。

In learning how to use grunt, I am trying to make a simple coffee-script watcher/compiler. The problem is, if I tell the watch task to watch several files, and one changes, it is going to pass all of the files to the coffee command. This means when you change 1 file, it's going to recompile all of the files matching the src pattern. Instead, I want to only recompile the single file that changed that matches the src pattern.

Here is the grunt.js:

module.exports = function(grunt) {
  grunt.initConfig({
    coffee: {
      app: {
        src: ['test/cases/controller/*.coffee'],
        dest: 'tmp',
        options: {
          bare: true,
          preserve_dirs: true
        }
      }
    },
    watch: {
      files: ['<config:coffee.app.src>'],
      tasks: ['coffee:app']
    }
  });

  grunt.loadNpmTasks('grunt-coffee');
  grunt.registerTask('default', 'coffee');
};

This is using grunt-coffee, which is basically this: https://gist.github.com/2373159.

When I run grunt watch, and I save a file in test/cases/controller/*.coffee, it compiles all of the matching files (putting them in tmp/*).

How do you instead only compile the changed file using grunt?

解决方案

The upcoming (and currently in-development) v0.4.0a grunt has the grunt.file.watchFiles object, which was designed expressly for this purpose. The grunt-coffee plugin may have added support for this feature already, I'm not sure.

Either way, if you're interested in trying an in-development version of grunt in your project, check out the When will I be able to use in-development feature 'X'? FAQ entry.

这篇关于你如何看待多个文件，但只能在Grunt.js中运行更改文件的任务？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！