从Servlet返回JSON响应到Javascript / JSP页面 [英] Returning JSON response from Servlet to Javascript/JSP page
问题描述
我认为(其实我知道!)我在这里做错了我正在尝试将一些值填充到HashMap中,并将每个hasmap添加到将添加到JSON对象的列表中:
I think (actually I KNOW!) I'm doing something wrong here I am trying to populate some values into HashMap and add each hasmap to a list which will be added to a JSON object:
JSONObject json = new JSONObject();
try
{
Map address;
List addresses = new ArrayList();
int count = 15;
for (int i=0 ; i<count ; i++)
{
address = new HashMap();
address.put("CustomerName" , "Decepticons" + i);
address.put("AccountId" , "1999" + i);
address.put("SiteId" , "1888" + i);
address.put("Number" , "7" + i);
address.put("Building" , "StarScream Skyscraper" + i);
address.put("Street" , "Devestator Avenue" + i);
address.put("City" , "Megatron City" + i);
address.put("ZipCode" , "ZZ00 XX1" + i);
address.put("Country" , "CyberTron" + i);
addresses.add(address);
}
json.put("Addresses", addresses);
}
catch (JSONException jse)
{
}
response.setContentType("application/json");
response.getWriter().write(json.toString());
我的问题是我知道这是返回一个字符串,我似乎无法解析(这是问题)。我的问题是,如何返回实际的JSON编码的字符串(或者甚至应该这样做?)或针对此类问题的最佳攻击方法是什么。我为此使用的JavaScript如下:
My problem is I know this is returning a string, which I cannot seem to parse (which is the problem). My question is how do I return the actual JSON encoded string (or even should I be doing this?) or what is the best method of attack for this type of problem. The JavaScript I am using for this is below:
function getReadyStateHandler(req)
{
// Return an anonymous function that listens to the
// XMLHttpRequest instance
return function ()
{
// If the request's status is "complete"
if (req.readyState == 4)
{
// Check that a successful server response was received
if (req.status == 200)
{
msgBox("JSON Response recieved...");
populateDatagrid(req.responseText.toJSON());
}
else
{
// An HTTP problem has occurred
alert("HTTP error: " + req.status);
}
}
}
}
JSON响应恢复正常,但它是一个字符串。任何意见是极大的赞赏。我也开放使用谷歌Gson,但没有太多的知识。
Note the JSON Response comes back fine, but its a string. Any advice is greatly appreciated. I am also opening to using googles Gson, but don't have too much knowledge on that.
推荐答案
得到它的工作!我应该一直在构建 JSONArray
的 JSONObject
s,然后将该数组添加到最终的Addresses的JSONObject
。注意以下几点:
Got it working! I should have been building a JSONArray
of JSONObject
s and then add the array to a final "Addresses" JSONObject
. Observe the following:
JSONObject json = new JSONObject();
JSONArray addresses = new JSONArray();
JSONObject address;
try
{
int count = 15;
for (int i=0 ; i<count ; i++)
{
address = new JSONObject();
address.put("CustomerName" , "Decepticons" + i);
address.put("AccountId" , "1999" + i);
address.put("SiteId" , "1888" + i);
address.put("Number" , "7" + i);
address.put("Building" , "StarScream Skyscraper" + i);
address.put("Street" , "Devestator Avenue" + i);
address.put("City" , "Megatron City" + i);
address.put("ZipCode" , "ZZ00 XX1" + i);
address.put("Country" , "CyberTron" + i);
addresses.add(address);
}
json.put("Addresses", addresses);
}
catch (JSONException jse)
{
}
response.setContentType("application/json");
response.getWriter().write(json.toString());
这个工作并返回了有效和可分析的JSON。希望这可以帮助未来的其他人。感谢您的帮助Marcel
This worked and returned valid and parse-able JSON. Hopefully this helps someone else in the future. Thanks for your help Marcel
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