GSON JsonObject“不支持的操作异常：null”符getAsString [英] GSON JsonObject "Unsupported Operation Exception: null" getAsString

问题描述

运行一个游戏！应用程序与斯卡拉。我正在做一个请求，其中的响应预计是一个JSON字符串。在检查调试器时，JsonElement会返回OK，包含所有预期的信息。但是，问题是当我尝试在该JsonElement上实际运行方法时。

  val json = WS.url（http： //maps.googleapis.com/maps/api/geocode/json?callback=?&sensor=true&address=%s，startAddress +，+ startCity +，+ startProvince）.get.getJson 
 val geocoder = json.getAsString 
  

我得到的唯一错误是 Unsupported操作异常：null 我在 getAsString 和 getAsJsonObject 和 getAsJsonPrimitive

任何想法为什么它在所有方法上失败？感谢。

可能是您的 JsonElement 是 JsonNull

你可以做的是首先检查它是否使用 json.isJsonNull

否则，请尝试使用 json.toString

Running a Play! app with Scala. I'm doing a request where the response is expected to be a JSON string. When checking the debugger, the JsonElement returns OK with all information as expected. However, the problem is when I try to actually run methods on that JsonElement.

val json = WS.url("http://maps.googleapis.com/maps/api/geocode/json?callback=?&sensor=true&address=%s", startAddress+","+startCity+","+startProvince).get.getJson
    val geocoder = json.getAsString

The only error I get back is Unsupported Operation Exception: null and I've tried this on getAsString and getAsJsonObject and getAsJsonPrimitive

Any idea why it's failing on all methods? Thanks.

解决方案

Maybe be your JsonElement is a JsonNull

What you could do is to first check that it isn't by using json.isJsonNull

Otherwise, try to get its String representation with json.toString

这篇关于GSON JsonObject“不支持的操作异常：null”符getAsString的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！