javascript,gulp,watch,改变了 [英] javascript, gulp, watch, changed
问题描述
我无法理解这一点。
这应该是每次观察文件被修改时执行的吞噬任务。任何人都可以解释为什么需要通过更改
插件来传输观看文件吗?
gulp.task('build-css',function(){
return gulp.src(paths.css)
.pipe(changed(paths.output,{extension:'.css '}))
.pipe(gulp.dest(paths.output));
});
$ b $ gulp.task('watch',['serve'],function(){
gulp.watch(paths.css,['build-css']);
});
免责声明:这不是我的代码。只是试图了解发生了什么,以创建我自己的自定义监视任务。 $ c> gulp.watch(), gulp-changed
和 gulp-watch
好像引起很多混乱,所以这里是我试图解开混乱:
gulp.watch()
这是三个中唯一一个 gulp
本身的一部分,而不是插件。这很重要,因为这意味着与其他两个不同,它不会被传递给gulp流的 pipe()
函数。
相反,它通常直接从gulp任务中调用:
$ $ $ $ $ $ $ $ gulp.task('build-css' ,function(){
return gulp.src('src / ** / *。css')
.pipe(doSomethingHere())
.pipe(gulp.dest('dist / css'));
});
$ b $ gulp.task('watch',function(){
gulp.watch('src / ** / * .css',['build-css']);
});
在上面的 gulp.watch()
用于侦听 .css
文件中的更改。只要 gulp.watch()
正在运行,对 .css
文件的任何更改都会自动导致执行 build-css
任务。
这是麻烦开始的地方。注意如何将哪些文件更改的信息传递给 build-css
?这意味着即使只更改了 .css
的一个 .css
文件全部文件将再次通过 doSomethingHere()
。 build-css
任务没有任何线索发生变化。这可能没有问题,只要你只有一堆文件,但会随着文件数量的增长而减慢你的构建。
这就是 gulp-changed
进来。
gulp-changed
这个插件是为了充当过滤阶段在吞噬流。其目的是从流中删除所有这些文件,这些文件自上一次构建以来没有改变过。它通过将源目录中的文件与目标目录中的结果文件进行比较来完成此操作:
gulp.task('build -css',function(){
return gulp.src('src / ** / * .css')
.pipe(更改('dist / css'))//比较文件dist / css
.pipe(doSomethingHere())
.pipe(gulp.dest('dist / css'));
});
$ b $ gulp.task('watch',function(){
gulp.watch('src / ** / * .css',['build-css']);
});
在上面的 build-css
任务仍然要求对 .css
文件进行每次更改,并读入所有 .css
文件。但只有这些文件现在已经改变现在到达昂贵的 doSomethingHere()
阶段。其余的被 gulp-changed
。
过滤出来。这种方法有加速 build-css
,即使您不在监视文件更改。您可以在命令行上显式调用 gulp build-css
,并且只有自上次调用 build-css
将被重建。
gulp-watch
这个插件是为了改进内置的 gulp.watch()
。虽然 gulp.watch()
使用 gaze
来监听文件更改, gulp-watch
使用 chokidar
这通常被认为是两者中较为成熟的。
您可以使用 gulp-watch
来达到与使用 gulp.watch()
和 gulp-changed
组合:
gulp.task(' watch'css',function(){
return gulp.src('src / ** / *。css')
.pipe(watch('src / ** / *。css'))
.pipe(doSomethingHere())
.pipe(gulp.dest('dist / css'));
});
这再次监视所有 .css
文件变化。但是这次只要 .css
文件被改变,那个文件(和只是那个文件)被再次读入并重新发送到它的流通过 doSomethingHere()
到达目的地目录。
请注意,这个比较在相当广泛的笔画中画出了所有三种选择,并留下了某些细节和功能(例如,我没有谈到可以传递给 gulp.watch的回调函数()
和 gulp-watch
),但我认为这应该足以让三者之间的主要区别得到解决。
I cannot get my head around this.
This is supposed to be a gulp task that is executed every time a watched file is modified. Can anyone explain why it is required to pipe the watched files through the changed
plugin?
gulp.task('build-css', function () {
return gulp.src(paths.css)
.pipe(changed(paths.output, {extension: '.css'}))
.pipe(gulp.dest(paths.output));
});
gulp.task('watch', ['serve'], function() {
gulp.watch(paths.css, ['build-css']);
});
Disclaimer: this is not my code. Just trying to understand what is going on, in order to create my own custom watch task.
The difference between gulp.watch()
, gulp-changed
and gulp-watch
seems to cause a lot of confusion, so here's my attempt at untangling the mess:
gulp.watch()
This is the only one of the three that is part of gulp
itself and not a plugin. This is important, because it means that unlike the other two it is not passed to the pipe()
function of a gulp stream.
Instead it is usually called directly from inside a gulp task:
gulp.task('build-css', function() {
return gulp.src('src/**/*.css')
.pipe(doSomethingHere())
.pipe(gulp.dest('dist/css'));
});
gulp.task('watch', function() {
gulp.watch('src/**/*.css', ['build-css']);
});
In the above gulp.watch()
is used to listen for changes in .css
files. As long as gulp.watch()
is running any change to a .css
file automatically results in the execution of the build-css
task.
This is where the trouble starts. Notice how no information about which files where changed is passed to build-css
? That means even if you change just a single .css
file all of your .css
files will pass through doSomethingHere()
again. The build-css
task has no clue which of them changed. This may be fine as long as you have only a hand full of files, but can slow down your build as the number of files grows.
That's where gulp-changed
comes in.
gulp-changed
This plugin was written to act as a filter stage in a gulp stream. Its purpose is to remove all those files from a stream that haven't changed since the last build. It does this by comparing the files in the source directory with the resulting files in the destination directory:
gulp.task('build-css', function() {
return gulp.src('src/**/*.css')
.pipe(changed('dist/css')) //compare with files in dist/css
.pipe(doSomethingHere())
.pipe(gulp.dest('dist/css'));
});
gulp.task('watch', function() {
gulp.watch('src/**/*.css', ['build-css']);
});
In the above the build-css
task is still called for every change of a .css
file and all .css
files are read in. However only those files that were actually changed now reach the expensive doSomethingHere()
stage. The rest is filtered out by gulp-changed
.
This approach has the benefit of speeding up build-css
even if you're not watching for file changes. You can explicitly invoke gulp build-css
on the command-line and only those files that have changed since the last invocation of build-css
will be rebuilt.
gulp-watch
This plugin is an attempt to improve on the built-in gulp.watch()
. While gulp.watch()
uses gaze
to listen for file changes, gulp-watch
uses chokidar
which is generally considered to be the more mature of the two.
You can use gulp-watch
to achieve the same effect as using gulp.watch()
and gulp-changed
in combination:
gulp.task('watch-css', function() {
return gulp.src('src/**/*.css')
.pipe(watch('src/**/*.css'))
.pipe(doSomethingHere())
.pipe(gulp.dest('dist/css'));
});
This again watches all .css
files for changes. But this time whenever a .css
file is changed, that file (and only that file) is read in again and reemitted to the stream where it passes through doSomethingHere()
on its way to the destination directory.
Note that this comparison paints all three of the alternatives in rather broad strokes and leaves out certain details and features (e.g. I haven't talked about the callback functions that you can pass to both gulp.watch()
and gulp-watch
), but I think this should be enough to get the major differences between the three across.
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