我正在写一个Accumulo迭代器来返回一个百分位表的随机样本 [英] I am looking at writing an Accumulo iterator to return a random sample of a percentile of a table

问题描述

如果有任何建议，我将不胜感激。

$ b

Thnaks，

Chris

解决方案

您可以扩展org.apache.accumulo.core.iterators.Filter并随机接受x％的条目。以下迭代器会随机返回5％的条目。

  import java.util.Random; 
 
 import org.apache.accumulo.core.data.Key; 
 import org.apache.accumulo.core.data.Value; 
 import org.apache.accumulo.core.iterators.Filter; 
 
 public class RandomAcceptFilter extends Filter {
 private Random rand = new Random（）; 
 
 @Override 
 public boolean accept（Key k，Value v）{
 return rand.nextDouble（）< 0.05; 
} 
} 
  

I am looking at writing an Accumulo iterator to return a random sample of a percentile of a table.

I would appreciate any suggestions.

Thnaks,

Chris

解决方案

You can extend org.apache.accumulo.core.iterators.Filter and randomly accept x% of the entries. The following iterator would randomly return 5 percent of the entries.

import java.util.Random;

import org.apache.accumulo.core.data.Key;
import org.apache.accumulo.core.data.Value;
import org.apache.accumulo.core.iterators.Filter;

public class RandomAcceptFilter extends Filter {
    private Random rand = new Random();

    @Override
    public boolean accept(Key k, Value v) {
        return rand.nextDouble() < .05;
    }
}

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