遍历zip文件java中的所有目录 [英] iterating over all directories in a zip file java

问题描述

我目前正在开发一个工具，允许我修改zip文件的md5。该文件的目录结构如下所示：

  baselines-> 
款 - >图标 - > 
 lang  - > 
（一堆文件）
  

然而，当我运行我的代码时，这些目录正在迭代进入。输出给我：

$ p $ 名称：model / visualization_dependency.xml
名称：model / visualization_template.xml
名称：model / weldmgmt_dependency.xml
名称：model / weldmgmt_template.xml


我是期望类似model / baseline / somefile.xml的东西会出现在输出中，但它不会。有什么想法吗？

  byte [] digest = null; 
 MessageDigest md5; 
 
尝试{
 md5 = MessageDigest.getInstance（MD5）; 
 
 ZipEntry current; （（current = entry.getNextEntry（））！= null）{
 
 // ZipEntry current = entry.getNextEntry（）; 
 System.out.println（Size：+ current.getSize（））; 
 System.out.println（Name：+ current.getName（））; （current.isDirectory（））{
 digest = this.encodeUTF8（current.getName（））; 
 
 if 
 md5.update（digest）; 
} 
 else {
 int size =（int）current.getSize（）; 
 digest =新字节[size]; 
 entry.read（digest，0，size）; 
 md5.update（digest）; 
} 
} 
 digest = md5.digest（）; 
 entry.close（）; 
} catch（NoSuchAlgorithmException e）{
 // TODO自动生成的catch块
 e.printStackTrace（）; 
 
  

解决方案

是目录，那么你需要迭代遍历目录中的每个文件并处理每个文件。

例子：

  if（current.isDirectory（））{ 
 System.out.println（Directory：+ file.getName（））; 
 //通过file.listFiles（）获取文件列表，并将它传递给
 //传递给将执行处理的其他方法。 
 digest = this.encodeUTF8（current.getName（））; 
 md5.update（digest）; 
 
  

---

检查这个问题，它细节过程很好。
在Java中对目录进行迭代

I'm currently developing a tool that would allow me to modify the md5 of a zip file. The directory structure of the file looks like

          baselines->
models -> icons    ->
          lang     ->
          (a bunch of files here)

However, when I run my code, none of those directories are getting iterating into. The output gives me:

Name:model/visualization_dependency.xml
Name:model/visualization_template.xml
Name:model/weldmgmt_dependency.xml
Name:model/weldmgmt_template.xml

I was expecting to something like model/baseline/somefile.xml appears on the output, but it does not. Any Thoughts?

byte[] digest = null;
        MessageDigest md5;

        try {
            md5 = MessageDigest.getInstance("MD5");

            ZipEntry current;
            while((current = entry.getNextEntry()) != null){

                //ZipEntry current = entry.getNextEntry();
                System.out.println("Size:" + current.getSize());
                System.out.println("Name:" + current.getName());

                if(current.isDirectory()){
                    digest = this.encodeUTF8(current.getName());
                    md5.update(digest);
                }
                else{
                    int size = (int)current.getSize();
                    digest = new byte[size];
                    entry.read(digest, 0, size);
                    md5.update(digest);
                }
            }
            digest = md5.digest();
            entry.close();
        } catch (NoSuchAlgorithmException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

解决方案

Once you check that existing folder is directory then you need to iterative go through each files in the directory and process each on of those.

Example:

if(current.isDirectory()){
  System.out.println("Directory: " + file.getName());
  //Get list of files by file.listFiles() and pass it to 
 // to other method that will do processing. 
  digest = this.encodeUTF8(current.getName());
  md5.update(digest);
}

---

Checkout this question, it details process well. Iterating inside directories in Java

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