显示YUV图像中的Andr​​oid [英] Displaying YUV Image in Android

问题描述

在我的应用程序，我们需要显示的视频帧接收从服务器到我们的Andr​​oid应用程序，
服务器发送视频数据@每秒50帧，有恩codeD中的WebM即采用libvpx为en code和德code中的图像，

In my application, we need to display the Video frame receives from server to our android application,
Server is sending video data @ 50 frame per second, having encoded in WebM i.e. using libvpx to encode and decode the images,

现在从libvpx其获得的YUV数据进行解码，我们就可以显示在图像上的布局后，

Now after decoding from libvpx its getting YUV data, that we can displayed over the image layout,

目前的执行情况是这样的，

the current implementation is something like this,

在JNI /本机C ++ code，我们将YUV数据为RGB数据 在Android框架，要求

In JNI / Native C++ code, we are converting YUV data to RGB Data In Android framework, calling

public Bitmap createImgae(byte[] bits, int width, int height, int scan) {
    Bitmap bitmap=null;
    System.out.println("video: creating bitmap");
    //try{

            bitmap = Bitmap.createBitmap(width, height,
                    Bitmap.Config.ARGB_8888);
            bitmap.copyPixelsFromBuffer(ByteBuffer.wrap(bits));     

    //}catch(OutOfMemoryError ex){

    //}
            System.out.println("video: bitmap created");
    return bitmap;
}  

要创建位图图像，

使用以下code来显示图像上ImageView的，

to display the image over imageView using following code,

               img = createImgae(imgRaw, imgInfo[0], imgInfo[1], 1);
               if(img!=null && !img.isRecycled()){

                    iv.setImageBitmap(img);
                    //img.recycle();
                    img=null;
                    System.out.println("video: image displayed");
                }

我的查询，总体来说，这一功能正在约40毫秒，有没有什么办法去优化它，
1 - 有什么办法来显示YUV数据的ImageView？

My query is, overall this function is taking approx 40 ms, is there any way to optimize it,
1 -- Is there any way to display YUV data to imageView ?

2 - 是否有任何其他的方法来创建图像（位图图像​​）的RGB数据，

2 -- Is there any other way to create Image( Bitmap image) from RGB data ,

3 - 我相信我总是创造的形象，但我想我应该始终创建位图只有​​一次，做/提供新的缓冲区，因为当我们收到
。  请分享你的看法。

3 -- I believe i am always creating image, but i suppose i should create bitmap only once and do / supply new buffer always, as and when we received.
please share your views.

推荐答案

随着code解决您的问题，它可能需要在YUV格式的数据的时间更少，因为YuvImage类提供了Android的SDK。

Following code solve your problem and it may take less time on Yuv Format data because YuvImage class is provided with Android-SDK.

您可以试试这个，

ByteArrayOutputStream out = new ByteArrayOutputStream();
YuvImage yuvImage = new YuvImage(data, ImageFormat.NV21, width, height, null);
yuvImage.compressToJpeg(new Rect(0, 0, width, height), 50, out);
byte[] imageBytes = out.toByteArray();
Bitmap image = BitmapFactory.decodeByteArray(imageBytes, 0, imageBytes.length);
iv.setImageBitmap(image);

或

void yourFunction(byte[] data, int mWidth, int mHeight)
{

int[] mIntArray = new int[mWidth*mHeight];

// Decode Yuv data to integer array
decodeYUV420SP(mIntArray, data, mWidth, mHeight);

//Initialize the bitmap, with the replaced color  
Bitmap bmp = Bitmap.createBitmap(mIntArray, mWidth, mHeight, Bitmap.Config.ARGB_8888);  

// Draw the bitmap with the replaced color  
iv.setImageBitmap(bmp);  

}

static public void decodeYUV420SP(int[] rgba, byte[] yuv420sp, int width,
    int height) {
final int frameSize = width * height;

for (int j = 0, yp = 0; j < height; j++) {
    int uvp = frameSize + (j >> 1) * width, u = 0, v = 0;
    for (int i = 0; i < width; i++, yp++) {
        int y = (0xff & ((int) yuv420sp[yp])) - 16;
        if (y < 0)
            y = 0;
        if ((i & 1) == 0) {
            v = (0xff & yuv420sp[uvp++]) - 128;
            u = (0xff & yuv420sp[uvp++]) - 128;
        }

        int y1192 = 1192 * y;
        int r = (y1192 + 1634 * v);
        int g = (y1192 - 833 * v - 400 * u);
        int b = (y1192 + 2066 * u);

        if (r < 0)
            r = 0;
        else if (r > 262143)
            r = 262143;
        if (g < 0)
            g = 0;
        else if (g > 262143)
            g = 262143;
        if (b < 0)
            b = 0;
        else if (b > 262143)
            b = 262143;

        // rgb[yp] = 0xff000000 | ((r << 6) & 0xff0000) | ((g >> 2) &
        // 0xff00) | ((b >> 10) & 0xff);
        // rgba, divide 2^10 ( >> 10)
        rgba[yp] = ((r << 14) & 0xff000000) | ((g << 6) & 0xff0000)
                | ((b >> 2) | 0xff00);
    }
}
}

这篇关于显示YUV图像中的Andr​​oid的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！