是否有任何haskell函数来连接列表与分隔符？ [英] Is there any haskell function to concatenate list with separator?

问题描述

是否有函数用分隔符连接列表元素？
例如：

 > foob​​ar[is，there，such，a，function，？] 
 [是否有这样的函数？] 
  
 $ b 
感谢您的回复！
 
解决方案
是的，有 ：
  Prelude> import Data.List 
 Prelude Data.List> intercalate[is，there，such，a，function，？] 
是否有这样的功能？ 
  
   intersperse  更具普遍性：
  Prelude> import Data.List 
 Prelude Data.List> concat（intersperse[is，there，such，a，function，？]）
有没有这样的函数？ 
  
另外，对于要用空格字符连接的特定情况，  unwords  ：
  Prelude> unwords [is，there，such，a，function，？] 
是否有这样的功能？ 
  
   unlines  的作用相似，只是字符串使用换行符字符，而且换行符也添加到最后。 （这对于序列化文本文件很有用，它必须按照POSIX标准结尾并带有尾随换行符）
 
Is there a function to concatenate elements of a list with a separator?
For example:
> foobar " " ["is","there","such","a","function","?"]
["is there such a function ?"]
Thanks for any reply!
解决方案
Yes, there is:
Prelude> import Data.List
Prelude Data.List> intercalate " " ["is","there","such","a","function","?"]
"is there such a function ?"
intersperse is a bit more general:
Prelude> import Data.List
Prelude Data.List> concat (intersperse " " ["is","there","such","a","function","?"])
"is there such a function ?"
Also, for the specific case where you want to join with a space character, there is unwords:
Prelude> unwords ["is","there","such","a","function","?"]
"is there such a function ?"
unlines works similarly, only that the strings are imploded using the newline character and that a newline character is also added to the end. (This makes it useful for serializing text files, which must per POSIX standard end with a trailing newline)

                        
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