在Haskell中,有没有infinity :: Num a =>一个? [英] In Haskell, is there infinity :: Num a => a?
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问题描述
我试图实现一个数据结构,如果我使用无穷大来进行数值比较,那么它就会非常简单。注意,这不是maxBound / minBound,因为一个值可以是<=最大值,但所有值都是<无穷无尽。
I'm trying to implement a data structure where if I had the use of infinity for numerical comparison purposes, it would simply things greatly. Note this isn't maxBound/minBound, because a value can be <= maxbound, but all values would be < infinity.
没有希望?
No hope?
推荐答案
类型?
data Infinite a = Infinite | Only a
然后为Num a => Infinite a写一个Num实例,并且需要数字规则。
then write a Num instance for Num a => Infinite a, with the numeric rules you need.
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