我想从我的资产或原始文件夹播放视频 [英] I want to play a video from my assets or raw folder

问题描述

我想打从我的资产或原始文件夹中的视频在我的Andr​​oid应用 使用 VideoView 我收到错误的视频无法播放 请谁能给我一个解决方案。

下面是code我用

  VideoView VD =（VideoView）findViewById（R.id.Video）;
开放的我们的uri = Uri.parse（android.resource：+ R.raw.video）;
的MediaController MC =新的MediaController（本）;
vd.setMediaController（MC）;
vd.setVideoURI（URI）;
vd.start（）;
 

解决方案

有几件事情需要注意：

1. 您必须复制视频到你的项目的 RES /生文件夹。
2. 这必须是一个支持的格式（3GP，WMV，MP4），并命名为小写字母，数字，下划线和在它的文件名点： my_video_file.mp4
3. 当您使用该资源在code，你将通过阵列生成的R静态参考 - 这将具有文件扩展名中删除： R.raw.my_video_file
4. 在该活动类有一个辅助方法getPackageName（），它可以构建正确的URI您的视频时，可以使用您的code。

  VideoView VV =（VideoView）this.findViewById（R.id.videoView）
串的uri =android.resource：//+ getPackageName（）+/+ R.raw.my_video_file;
vv.setVideoURI（Uri.parse（URI））;
vv.start（）;
 

有更多这方面的信息，<一个href="http://javatech.org/2011/01/discovering-android-embedding-video-in-an-android-application/">here.

I want to play a video from my assets or raw folder in my app in Android using VideoView I am getting the error as video cannot be played please anyone give me a solution.

Here is the code I used

VideoView vd = (VideoView)findViewById(R.id.Video);         
Uri uri = Uri.parse("android.resource:"  + R.raw.video);
MediaController mc = new MediaController(this);
vd.setMediaController(mc);
vd.setVideoURI(uri); 
vd.start();

解决方案

A few things to note:

1. You must copy the video into your project's res/raw folder.
2. It must be in a supported format (3gp, wmv, mp4 ) and named with lower case, numerics, underscores and dots in its filename: my_video_file.mp4
3. When you work with this resource in code, you will reference through the generated R statics - it will have the file extension removed: R.raw.my_video_file
4. The Activity class has a helper method getPackageName() which can be used by your code when constructing the correct URI to your video.

VideoView vv = (VideoView)this.findViewById(R.id.videoView)
String uri = "android.resource://" + getPackageName() + "/" + R.raw.my_video_file;
vv.setVideoURI(Uri.parse(uri));
vv.start();

There is more information on this here.

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