转换一个“大”十六进制数字(字符串格式)转换为不带BigInteger Class的十进制数字(字符串格式) [英] Convert a "big" Hex number (string format) to a decimal number (string format) without BigInteger Class

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本文介绍了转换一个“大”十六进制数字(字符串格式)转换为不带BigInteger Class的十进制数字(字符串格式)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何转换一个 大 的十六进制数字(字符串格式):

How to convert a "big" Hex number (in string format):

EC851A69B8ACD843164E10CFF70CF9E86DC2FEE3CF6F374B43C854E3342A2F1AC3E30C741CC41E679DF6D07CE6FA3A66083EC9B8C8BF3AF05D8BDBB0AA6CB3EF8C5BAA2A5E531BA9E28592F99E0FE4F95169A6C63F635D0197E325C5EC76219B907E4EBDCD401FB1986E4E3CA661FF73E7E2B8FD9988E753B7042B2BBCA76679

EC851A69B8ACD843164E10CFF70CF9E86DC2FEE3CF6F374B43C854E3342A2F1AC3E30C741CC41E679DF6D07CE6FA3A66083EC9B8C8BF3AF05D8BDBB0AA6CB3EF8C5BAA2A5E531BA9E28592F99E0FE4F95169A6C63F635D0197E325C5EC76219B907E4EBDCD401FB1986E4E3CA661FF73E7E2B8FD9988E753B7042B2BBCA76679

为十进制数(以字符串格式):

to a decimal number (in string format):

166089946137986168535368849184301740204613753693156360462575217560130904921953976324839782808018277000296027060873747803291797869684516494894741699267674246881622658654267131250470956587908385447044319923040838072975636163137212887824248575510341104029461758594855159174329892125993844566497176102668262139513

166089946137986168535368849184301740204613753693156360462575217560130904921953976324839782808018277000296027060873747803291797869684516494894741699267674246881622658654267131250470956587908385447044319923040838072975636163137212887824248575510341104029461758594855159174329892125993844566497176102668262139513

不使用 BigInteger Class(因为我的应用程序应该支持没有.NET Framework 4的机器) ?

without using BigInteger Class (as my application should support machines without .NET Framework 4)?

推荐答案

这是一个快速安装可以使用任意大数字的d-dirty实现。这种实现的目的是简单而不是性能;因此,如果要在生产场景中使用,应该进行大幅优化。

Here's a quick-and-dirty implementation that can work with arbitrarily-large numbers. The aim of this implementation is simplicity, not performance; thus, it should be optimized drastically if it's to be used in a production scenario.

编辑:根据DanByström的逆十进制到十六进制转换

Edit: Simplified further per Dan Byström's implementation of the inverse decimal-to-hex conversion:

static string HexToDecimal(string hex)
{
    List<int> dec = new List<int> { 0 };   // decimal result

    foreach (char c in hex)
    {
        int carry = Convert.ToInt32(c.ToString(), 16);   
            // initially holds decimal value of current hex digit;
            // subsequently holds carry-over for multiplication

        for (int i = 0; i < dec.Count; ++i)
        {
            int val = dec[i] * 16 + carry;
            dec[i] = val % 10;
            carry = val / 10;
        }

        while (carry > 0)
        {
            dec.Add(carry % 10);
            carry /= 10;
        }
    }

    var chars = dec.Select(d => (char)('0' + d));
    var cArr = chars.Reverse().ToArray();
    return new string(cArr);
}

这篇关于转换一个“大”十六进制数字(字符串格式)转换为不带BigInteger Class的十进制数字(字符串格式)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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