C＃构建十六进制表示法字符串 [英] C# Build hexadecimal notation string

问题描述

我如何以十六进制表示法构建转义序列字符串。

How do I build an escape sequence string in hexadecimal notation.

示例：

Example:

string s = "\x1A"; // this will create the hex-value 1A or dec-value 26

我希望能够使用十六进制值在00到FF之间构建字符串（在本例中为1B）

I want to be able to build strings with hex-values between 00 to FF like this (in this example 1B)

string s = "\x" + "1B"; // Unrecognized escape sequence

也许还有另一种制作十六进制字符串的方法...

Maybe there's another way of making hexadecimal strings...

推荐答案

您不会在字符串中存储十六进制值。

You don't store hexadecimal values in strings.

你可以，但它只是一个字符串，必须转换为整数或字节才能真正读取它的值。

You can, but it would just be that, a string, and would have to be cast to an integer or a byte to actually read its value.

您可以将一个十六进制值作为一个文字分配给一个int或一个字节：

You can assign a hexadecimal value as a literal to an int or a byte though:

Byte value = 0x0FF;
int value = 0x1B;

所以，它很容易将十六进制字面值传递到字符串中：

So, its easily possible to pass an hexadecimal literal into your string:

string foo = String.Format("{0} hex test", 0x0BB);

哪个会创建这个字符串126 hex test。

Which would create this string "126 hex test".

但我不认为这就是你想要的？

But I don't think that's what you wanted?

这篇关于C＃构建十六进制表示法字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！