Java - 解析并将无符号十六进制字符串解析为带符号的long [英] Java - parse and unsigned hex string into a signed long

问题描述

  d1bc4f7154ac9edb 
 
我有一堆十六进制字符串，其中之一就是： code> 

这是-3333702275990511909的十六进制值。如果你做了Long.toHexString（d1bc4f7154ac9edb）;



现在，我们假设我只能访问十六进制字符串值，这就对了。这样做：

  Long.parseLong（hexstring，16）; 
  

不起作用，因为它会将其转换为对于Long而言太大的不同值。是否有将这些无符号十六进制值转换为带符号的长整数？

谢谢！

解决方案

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您可以使用 BigInteger 来解析它并获取一个 long ：

  long value = new BigInteger（d1bc4f7154ac9edb，16）.longValue（）; 
 System.out.println（value）; // this outputs -3333702275990511909 
  

I have a bunch of hex strings, one of them, for example is:

  d1bc4f7154ac9edb

which is the hex value of "-3333702275990511909". This is the same hex you get if you do Long.toHexString("d1bc4f7154ac9edb");

For now, let's just assume I only have access to the hex string values and that is it. Doing this:

  Long.parseLong(hexstring, 16);

Doesn't work because it converts it to a different value that is too large for a Long. Is there away to convert these unsigned hex values into signed longs?

Thanks!

解决方案

You can use BigInteger to parse it and get back a long:

long value = new BigInteger("d1bc4f7154ac9edb", 16).longValue();
System.out.println(value); // this outputs -3333702275990511909

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