你如何映射一个“地图”在冬眠使用注释? [英] How do you map a "Map" in hibernate using annotations?
问题描述
使用注释如何将字符串中的字段映射到String的Map(Hashtable)到给定对象?这个对象被注解了,它的实例已经存储在hibernate数据库中。
我发现了用简单的键和值定义映射的语法:
$ b
< class name =Footable =foo>
...
<地图角色=年龄>
< key column =id/>
< index column =nametype =string/>
< element column =agetype =string/>
< / map>
< / class>
奇怪的是一个实体作为键和一个简单类型,就像这样:
< class name =Footable =foo>
...
<地图角色=年龄>
< key column =id/>
class =Person/>
< element column =agetype =string/>
< / map>
< / class>
< class name =Persontable =person>
...
type =string/>
< / class>
但是我不知道如何做到这一点,您可以简单地使用 JPA注释
code> @MapKey (请注意,JPA注释与Hibernate不同,Hibernate @MapKey
映射一个保存地图键的数据库列,while JPA的注解映射了要用作映射关键字的属性)。pre $
@ javax.persistence.OneToMany(cascade = CascadeType。 ALL)
@ javax.persistence.MapKey(name =name)
private Map< String,Person> nameToPerson = new HashMap< String,Person>();
Using annotations how do you map a field in an entity which is a "Map" (Hashtable) of String to a given object? The object is annotated and instances of it are already stored in the hibernate databse.
I've found the syntax for definging a map with a simple key and value as such:
<class name="Foo" table="foo">
...
<map role="ages">
<key column="id"/>
<index column="name" type="string"/>
<element column="age" type="string"/>
</map>
</class>
And oddly with an entity as the key and a simple type as the value like so:
<class name="Foo" table="foo">
...
<map role="ages">
<key column="id"/>
<index-many-to-many column="person_id"
class="Person"/>
<element column="age" type="string"/>
</map>
</class>
<class name="Person" table="person">
...
<property name="name" column="name"
type="string"/>
</class>
But I don't see how to do this for a simple key to element mapping, and I don't see how to do this using annotations.
You could simply use the JPA annotation @MapKey
(note that the JPA annotation is different from the Hibernate one, the Hibernate @MapKey
maps a database column holding the map key, while the JPA's annotation maps the property to be used as the map's key).
@javax.persistence.OneToMany(cascade = CascadeType.ALL)
@javax.persistence.MapKey(name = "name")
private Map<String, Person> nameToPerson = new HashMap<String, Person>();
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