如何使用jpa / hibernate在playframework子模块中保存模型实体 [英] How to persist models entity in playframework submodule using jpa/hibernate
问题描述
每个子模块都有这样的文件夹结构：
- 应用：
- 控制器
- 模型 b $ b
- views
- submodulename.routes / li>
- build.sbt
喜欢在文件夹中坚持所有的java类实体： models 。
我应该如何配置play framework和/或hibernate entity manager来扫描这个文件夹
我有一个示例模型类，如下所示：
包models.common;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.ManyToOne;
import javax.persistence.NoResultException;
import controllers.common.Index;
import play.data.validation.Constraints;
导入play.db.jpa.JPA;
$ b $ @Entity
public class AppMode {
public static AppMode getCurrentConfigurationEntry（）{
return JPA.em（）。find（AppMode.class，1L）;
}
//其余代码在这里 - 不重要//
}
但在这种状态下，jvm返回一个运行时错误：
pre $ [IllegalArgumentException：Unknown entity：models.common.AppMode ]
注：我正在使用play 2.2.1
我注意到，当我在persistance.xml中设置时，hibernate正确地为AppMode实体
创建了sql结构：
< property name =hibernate.hbm2ddl.autovalue =create-drop/>
但是当我走得更远时，我得到了下一个错误：
[IllegalArgumentException：org.hibernate.hql.ast.QuerySyntaxException：MIncident未映射
虽然我在该类上注解了@Entity。
这似乎是正确的映射，但我不能做任何像 hsql select 或 JPA.em（）。find（）这样的实体操作
我自己解决了这个问题。
运行时错误： p>
[IllegalArgumentException：未知实体：models.common.AppMode]
由Jpa / Hibernate配置引起。问题是Jpa / Hibernate在编译时看到我的实体（标注@Entity），但是在运行时dosn't。要解决这个问题，我必须手动将所有模型类（实体）指向persistance.xml文件中，如下所示：
/conf/META-INF/persistence.xml
< persistence xmlns =http://java.sun.com/xml/ns/persistence
xmlns ：xsi =http://www.w3.org/2001/XMLSchema-instance
xsi：schemaLocation =http://java.sun.com/xml/ns/persistence http：// java。 sun.com/xml/ns/persistence/persistence_2_0.xsd
version =2.0>
< persistence-unit name =defaultPersistenceUnittransaction-type =RESOURCE_LOCAL>
< provider> org.hibernate.ejb.HibernatePersistence< / provider>
<非-jta-data-source> DefaultDS< /非-jta-data-source>
< class> models.common.AppMode< / class>
< class> models.Customer< / class>
< class> models.Complaint< / class>
<属性>
< property name =hibernate.hbm2ddl.autovalue =update/>
< property name =hibernate.dialectvalue =org.hibernate.dialect.H2Dialect/>
< property name =hibernate.show_sqlvalue =true/>
< / properties>
< / persistence-unit>
< /余辉>
原文：
在Play Framework中的子项目类中的包名称（名称空间）
我想知道为什么在主项目（fe： /app/models/User.java ）我可以使用注释 @javax。 persistence.Entity （它有效），但是在子项目中（fe： /modules/common/app/models/AppMode.java ）它dosnt工作时，注释 @ javax.persistence.Entity 不够，我必须将每个模型类指向persistance.xml文件。
我认为这是一个playframework中的错误（我检查过2.2.1,2.2.4和2.3.4版本）
I have project in PLAY FRAMEWORK wich contain few submodules.
Each submodule has folder structure like this:
- app:
- controllers
- models
- views
- conf:
- submodulename.routes
- build.sbt
I would like to persist all java class entities in folder: models.
How should I configure play framework and/or hibernate entity manager to scan this folders for entities.
I have example model class as follow:
package models.common;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.ManyToOne;
import javax.persistence.NoResultException;
import controllers.common.Index;
import play.data.validation.Constraints;
import play.db.jpa.JPA;
@Entity
public class AppMode {
public static AppMode getCurrentConfigurationEntry() {
return JPA.em().find(AppMode.class, 1L);
}
//rest of code here- not important//
}
but in this state jvm return me a runtime error:
[IllegalArgumentException: Unknown entity: models.common.AppMode]
NOTE : I'm using play 2.2.1
I've noticed that hibernate is correctly create sql structure for AppMode entity when I set this in persistance.xml:
<property name="hibernate.hbm2ddl.auto" value="create-drop"/>
But when I go further I am getting next error:
[IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: MIncident is not mapped
While I have annotation @Entity on that class.
It seems to be correct mapped, but I cant do any operation like hsql select or JPA.em().find() on that entities
I figure it out on my own.
Runtime error:
[IllegalArgumentException: Unknown entity: models.common.AppMode] Is caused by Jpa/Hibernate configuration. Problem is that Jpa/Hibernate sees my entities (mark by annotation @Entity) while compilation, but in runtime dosn't. To fix that I've to manually point all my models class (entitites) in persistance.xml file as follow:
/conf/META-INF/persistence.xml
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="defaultPersistenceUnit" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<non-jta-data-source>DefaultDS</non-jta-data-source>
<class>models.common.AppMode</class>
<class>models.Customer</class>
<class>models.Complaint</class>
<properties>
<property name="hibernate.hbm2ddl.auto" value="update"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.H2Dialect"/>
<property name="hibernate.show_sql" value="true"/>
</properties>
</persistence-unit>
</persistence>
Original post: package names (namespaces) in subproject classes in Play Framework
I wonder why in main project (f.e: /app/models/User.java) I can use annotation @javax.persistence.Entity (and it works), but in sub project (f.e: /modules/common/app/models/AppMode.java) it dosnt work, the annotation @javax.persistence.Entity is not enought, I have to point each model class in persistance.xml file.
I think it is a bug in playframework (I've checked 2.2.1, 2.2.4, and 2.3.4 versions)
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