在hibernate标准中使用sum和算术结果作为顺序键 [英] Using sum and arithmetic result as order key in hibernate criteria
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问题描述
SELECT anId,SUM(fieldA)AS A,SUM(fieldB) )AS B,SUM(fieldA)+ SUM(fieldB)AS'total'FROM tableA GROUP BY anId ORDER BY'total'DESC LIMIT 5
解决方案
以下条件应该可以做到这一点:
Criteria criteria = hibernateSession
.createCriteria(YourEntity.class);
criteria.setProjection(Projections
.projectionList()
.add(Projections.property(anId)。as(prop1))
.add(Projections.sum (fieldA)。as(prop2))
.add(Projections.sum(fieldB)。as(prop3))
.add(Projections.sqlProjection(
sum(fieldA)+ sum(fieldB)as total,
new String [] {total},
new Type [] {StandardBasicTypes.INTEGER}),total)
.add(Projections.groupProperty(remarks)));
criteria.addOrder(Order.desc(total));
criteria.setMaxResults(5);
criteria.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP);
List list = criteria.list();
for(Object object:list){
Map< Object,Object> map =(Map< Object,Object>)对象;
System.out.println(map);
}
How can I express this query in hibernate criteria.
SELECT anId, SUM(fieldA) AS A, SUM(fieldB) AS B, SUM(fieldA)+SUM(fieldB) AS 'total' FROM tableA GROUP BY anId ORDER BY 'total' DESC LIMIT 5
解决方案
following criteria should do the trick
Criteria criteria = hibernateSession
.createCriteria(YourEntity.class);
criteria.setProjection(Projections
.projectionList()
.add(Projections.property("anId").as("prop1"))
.add(Projections.sum("fieldA").as("prop2"))
.add(Projections.sum("fieldB").as("prop3"))
.add(Projections.sqlProjection(
"sum(fieldA) + sum(fieldB) as total",
new String[] { "total" },
new Type[] { StandardBasicTypes.INTEGER }), "total")
.add(Projections.groupProperty("remarks")));
criteria.addOrder(Order.desc("total"));
criteria.setMaxResults(5);
criteria.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP);
List list = criteria.list();
for (Object object : list) {
Map<Object, Object> map = (Map<Object, Object>) object;
System.out.println(map);
}
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