如何在使用@OneToOne和@OneToMany时创建Hibernate OUTER JOIN [英] How can I make Hibernate OUTER JOIN when using @OneToOne and @OneToMany
问题描述
假设我有一个名为 employee
的表,其中 employee_id
, name
和
supervisor_id
和
employee_supervisor
字段为 supervisor_id
和名称
。对于 supervisor_id 雇员
和 employee_supervisor
表存在外键关系。 code>列。
如果我在 Employee
类中做了多对一的注解映射,我该如何确保Hibernate使用LEFT OUTER JOIN加入相关实体?
在我的测试中,Hibernate默认做了LEFT OUTER JOIN。但是,您可以确保它始终使用带注释的LEFT OUTER JOIN。我花了一些时间嘲笑你的情况,使用从我的模板作为基地的双向一对多映射,然后更改类名以符合您的情况。
我想出的类如下所示:
EmployeeSupervisor类:
@Entity(name =EMPLOYEE_SUPERVISOR)
公共类EmployeeSupervisor {
@Id
@GenericGenerator(name =gen,strategy =increment)
@GeneratedValue(generator =gen)
@Column(name =id)
private int supervisorId ;
@Column
私人字符串名称;
@OneToMany(mappedBy =supervisor)
私人清单<员工>雇员;
....
}
员工类别:
@Entity
public class Employee {
@Id
@GenericGenerator(name =gen,strategy = 增量)
@GeneratedValue(generator =gen)
@Column(name =id)
private int employeeId;
@Column
私人字符串名称;
@ManyToOne
@Fetch(FetchMode.JOIN)
@JoinColumn(name =supervisorId)
私人EmployeeSupervisor监督员;
....
}
注释确保您始终使用 LEFT OUTER JOIN
是 @Fetch(FetchMode.JOIN
>注释,它告诉Hibernate加载关联的记录使用 LEFT OUTER JOIN
的相同select语句(参见其他类型 FetchMode
的文档,以及每个类型的内容)。然后,我在jUnit中模拟了数据库,配置Hibernate在log4j中打印所有生成的SQL
log4j.logger.org.hibernate.SQL = DEBUG
log4j.logger.org.hibernate.type = TRACE
并且运行了一个非常基本的单元测试。
public class EmployeeDAOTest扩展SpringTest {
@Autowired
private Employe eDAO dao;
私人员工testLinkedEmployee;
私人员工testUnlinkedEmployee;
私人EmployeeSupervisor testSupervisor;
@BeforeClass
public static void setUpBeforeClass()抛出异常{
System.out.println(Starting DAO Test);
@AfterClass
public static void tearDownAfterClass()抛出异常{
System.out.println(Finished DAO Test);
}
@Before
public void setUp()抛出Exception {
//不相关的可怕设置代码被剪掉。
/ *在数据库中设置2名员工和一名EmployeeSupervisor。
*将一名员工链接到EmployeeSupervisor,而不是其他
* /
}
@Test
@Transactional
public void test ){
Employee actualLinkedEmployee = dao.getEmployee(testLinkedEmployee.getEmployeeId());
Employee actualUnlinkedEmployee = dao.getEmployee(testUnlinkedEmployee.getEmployeeId());
assertNotNull(链接的员工的主管没有被选中,actualLinkedEmployee.getSupervisor());
assertNull(未关联的员工的主管不为空,actualUnlinkedEmployee.getSupervisor());
我的DAO非常简单:
@Repository
public class EmployeeDAOImpl implements EmployeeDAO {
$ b $ @Autowired
private SessionFactory sessionFactory;
@Override
public Employee getEmployee(int id){
Criteria query = sessionFactory.getCurrentSession()。createCriteria(Employee.class);
query.add(Restrictions.idEq(id));
return(Employee)query.uniqueResult();
}
}
和SQL输出如下:
[junit] / *条件查询* / select
[junit] this_.id as id1_1_1_ ,
[junit] this_.name as name2_1_1_,
[junit] this_.supervisorId as supervis3_1_1_,
[junit] employeesu2_.id as id1_0_0_,
[junit] employeesu2_.name as name2_0_0_
[junit] from
[junit] Employee this_
[junit] left outer join
[junit] EMPLOYEE_SUPERVISOR employeesu2_
[junit] this_.supervisorId = employeesu2_.id
[junit]其中
[junit] this_.id =? 01:23:54:0.668
[junit] binding parameter [1] as [INTEGER] - 5 01:23:54:0.671
[junit] / *条件查询* / select
[junit] this_.id as id1_1_1_,
[junit] this_.name as name2_1_1_,
[junit] this_.supervisorId as supervis3_1_1_,
[junit] employeesu2_.id as id1_0_0_,
[junit] employeesu2_.name as name2_0_0_
[junit] from
[junit] Employee this_
[junit] left outer join
[junit] EMPLOYEE_SUPERVISOR employeesu2_
[junit] on this_.supervisorId = employeesu2_.id
[junit]其中
[junit] this_.id =? 01:23:54:0.704
[junit] binding parameter [1] as [INTEGER] - 6 01:23:54:0.704
应该注意的是,默认情况下,Hibernate似乎急于获取这些实体并使用LEFT OUTER JOIN来执行此操作。但是,如果尝试将默认获取类型设置为 FetchType.LAZY
,则连接类型将更改为 FetchMode.SELECT
,并且只为员工发出单一选择,而不选择主管。
设置 FetchType.LAZY
与 @Fetch(FetchMode.JOIN)
但是,会覆盖您的懒惰抓取并使用连接急切地抓取您的主管。
Suppose I have a table called employee
with fields of employee_id
, name
and supervisor_id
and
employee_supervisor
with fields of supervisor_id
and name
. There is a foreign key relationship the employee
and employee_supervisor
table with respect to the supervisor_id
column.
If I do a many to one annotation mapping in the Employee
class, how can I make sure that Hibernate uses a LEFT OUTER JOIN to join the associated entities?
In my testing Hibernate did a LEFT OUTER JOIN by default. However you can ensure that it will always use a LEFT OUTER JOIN with annotations. I spent some time mocking up your situation using the bi-directional one to many mapping from my templates as a base, and then changing class names to match your situation.
The classes I came up with are as follows:
EmployeeSupervisor class:
@Entity(name="EMPLOYEE_SUPERVISOR")
public class EmployeeSupervisor {
@Id
@GenericGenerator(name = "gen", strategy = "increment")
@GeneratedValue(generator = "gen")
@Column(name = "id")
private int supervisorId;
@Column
private String name;
@OneToMany(mappedBy = "supervisor")
private List<Employee> employees;
....
}
Employee class:
@Entity
public class Employee {
@Id
@GenericGenerator(name = "gen", strategy = "increment")
@GeneratedValue(generator = "gen")
@Column(name = "id")
private int employeeId;
@Column
private String name;
@ManyToOne
@Fetch(FetchMode.JOIN)
@JoinColumn(name = "supervisorId")
private EmployeeSupervisor supervisor;
....
}
The annotation that ensures that you will always use a LEFT OUTER JOIN
is the @Fetch(FetchMode.JOIN
annotation. This tells Hibernate to load the associated record in the same select statement using a LEFT OUTER JOIN
(see the documentation for the other types of FetchMode
's and what each one does).
I then mocked up the database in jUnit, configured Hibernate to print all the generated SQL's in log4j
log4j.logger.org.hibernate.SQL=DEBUG
log4j.logger.org.hibernate.type=TRACE
and ran a pretty basic unit test.
public class EmployeeDAOTest extends SpringTest{
@Autowired
private EmployeeDAO dao;
private Employee testLinkedEmployee;
private Employee testUnlinkedEmployee;
private EmployeeSupervisor testSupervisor;
@BeforeClass
public static void setUpBeforeClass() throws Exception {
System.out.println("Starting DAO Test");
}
@AfterClass
public static void tearDownAfterClass() throws Exception {
System.out.println("Finished DAO Test");
}
@Before
public void setUp() throws Exception {
//Irrelevant horrible setup code snipped.
/* Set up 2 employees and a EmployeeSupervisor in the database.
* Link one employee to the EmployeeSupervisor and not the other
*/
}
@Test
@Transactional
public void test() {
Employee actualLinkedEmployee = dao.getEmployee(testLinkedEmployee.getEmployeeId());
Employee actualUnlinkedEmployee = dao.getEmployee(testUnlinkedEmployee.getEmployeeId());
assertNotNull("The linked employee's supervisor didn't get selected.", actualLinkedEmployee.getSupervisor());
assertNull("The unlinked employee's supervisor was not null.", actualUnlinkedEmployee.getSupervisor());
}
}
My DAO is exceedingly rudimentary:
@Repository
public class EmployeeDAOImpl implements EmployeeDAO {
@Autowired
private SessionFactory sessionFactory;
@Override
public Employee getEmployee(int id) {
Criteria query = sessionFactory.getCurrentSession().createCriteria(Employee.class);
query.add(Restrictions.idEq(id));
return (Employee) query.uniqueResult();
}
}
and the SQL output is as follows:
[junit] /* criteria query */ select
[junit] this_.id as id1_1_1_,
[junit] this_.name as name2_1_1_,
[junit] this_.supervisorId as supervis3_1_1_,
[junit] employeesu2_.id as id1_0_0_,
[junit] employeesu2_.name as name2_0_0_
[junit] from
[junit] Employee this_
[junit] left outer join
[junit] EMPLOYEE_SUPERVISOR employeesu2_
[junit] on this_.supervisorId=employeesu2_.id
[junit] where
[junit] this_.id = ? 01:23:54:0.668
[junit] binding parameter [1] as [INTEGER] - 5 01:23:54:0.671
[junit] /* criteria query */ select
[junit] this_.id as id1_1_1_,
[junit] this_.name as name2_1_1_,
[junit] this_.supervisorId as supervis3_1_1_,
[junit] employeesu2_.id as id1_0_0_,
[junit] employeesu2_.name as name2_0_0_
[junit] from
[junit] Employee this_
[junit] left outer join
[junit] EMPLOYEE_SUPERVISOR employeesu2_
[junit] on this_.supervisorId=employeesu2_.id
[junit] where
[junit] this_.id = ? 01:23:54:0.704
[junit] binding parameter [1] as [INTEGER] - 6 01:23:54:0.704
It should be noted that by default Hibernate seems to be eagerly fetching these entities and uses a LEFT OUTER JOIN to do so. However if you try and set the default fetch type to be FetchType.LAZY
then the join type changes to a FetchMode.SELECT
and just issues a single select for the employee without selecting the supervisor as well.
Setting FetchType.LAZY
with @Fetch(FetchMode.JOIN)
however, overrides your lazy fetching and uses a join to eagerly fetch your supervisor.
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