带有Hibernate数据保存错误的Spring MVC [英] Spring MVC with Hibernate Data Saving Error
问题描述
我无法正确持续使用汽车。从下拉菜单中选择公司。
我的控制器
@RequestMapping(/)
public String view(ModelMap model){
Map< String,String> companyList = new HashMap< String,String>();
清单<公司>公司= companyService.listAllCompanies();
for(Company company:companies){
companyList.put(String.valueOf(company.getId()),company.getName());
}
model.addAttribute(companies,companyList);
model.addAttribute(汽车,新汽车());
返回汽车/指数;
}
@RequestMapping(manage)
public String manage(@ModelAttribute Automotive汽车,
BindingResult结果,ModelMap模型){
模型。 addAttribute(汽车,汽车);
地图< String,String> companyList = new HashMap< String,String>();
清单<公司> companies = new ArrayList< Company>();
for(Company company:companies){
companyList.put(String.valueOf(company.getId()),company.getName());
}
model.addAttribute(companies,companyList);
automotiveService.addAutomotive(汽车);
返回汽车/指数;
}
我的视图
< form:form action =/ Automotive / managemodelAttribute =automotive>
名称:< form:input path =name/>
说明:< form:input path =description/>
类型:< form:input path =type/>
公司:< form:select path =companyitems =$ {companies}/>
< input type =submit/>
< / form:form>
Q1>从逻辑上看,公司ID不会被保存,保存它应该是一个公司类型的对象。我应该如何解决这个问题。我需要使用DTO还是有直接方法?
Q2>我不能直接通过公司列表来查看,而不是在控制器中创建新的地图吗?
您可以使用公司的id作为密钥,然后使用转换器,它会自动将数据从表单转换为域对象。就像在这段代码中一样:
public class CompanyIdToInstanceConverter实现了Converter< String,Company> {
@Inject
私人CompanyService _companyService;
@Override
public公司转换(final String companyIdStr){
return _companyService.find(Long.valueOf(companyIdStr));
}
}
在JSP中:
< form:select path =companyitems =$ {companies}itemLabel =nameitemValue =id/ >
如果您尚未触及此类型,您可能需要详细了解类型转换。它在Spring doc中有完美的描述(我找不到: http://static.springsource.org/spring/docs/3.0.x/reference/validation.html 第5.5段)。
我希望它会帮助你。
I have two tables: Company and Automotive. A company can have many automotives. I am unable to persist an Automotive properly. Company is selected in View page from a drop down.
My Controller
@RequestMapping("/")
public String view(ModelMap model) {
Map<String, String> companyList = new HashMap<String, String>();
List<Company> companies = companyService.listAllCompanies();
for (Company company : companies) {
companyList.put(String.valueOf(company.getId()), company.getName());
}
model.addAttribute("companies", companyList);
model.addAttribute("automotive", new Automotive());
return "automotive/index";
}
@RequestMapping("manage")
public String manage(@ModelAttribute Automotive automotive,
BindingResult result, ModelMap model) {
model.addAttribute("automotive", automotive);
Map<String, String> companyList = new HashMap<String, String>();
List<Company> companies = new ArrayList<Company>();
for (Company company : companies) {
companyList.put(String.valueOf(company.getId()), company.getName());
}
model.addAttribute("companies", companyList);
automotiveService.addAutomotive(automotive);
return "automotive/index";
}
My View
<form:form action="/Automotive/manage" modelAttribute="automotive">
Name : <form:input path="name" />
Description : <form:input path="description" />
Type : <form:input path="type" />
Company : <form:select path="company" items="${companies}" />
<input type="submit" />
</form:form>
Q1> Logically as expected Company id would not be saved since here in view its an id but actually while saving it should be an object of type company. How should I solve this. Do I need to use a DTO or is there any direct method?
Q2> Can't i pass Company list directly to view instead of creating a new Map in controller?
You can use id of company as a key and then use converter which will automatically convert data from form into domain object. Just like in this code:
public class CompanyIdToInstanceConverter implements Converter<String, Company> {
@Inject
private CompanyService _companyService;
@Override
public Company convert(final String companyIdStr) {
return _companyService.find(Long.valueOf(companyIdStr));
}
}
And in JSP:
<form:select path="company" items="${companies}" itemLabel="name" itemValue="id"/>
You may need to read more about type conversion if you haven't touched this yet. It is perfectly described in Spring doc (I you couldn't find: http://static.springsource.org/spring/docs/3.0.x/reference/validation.html paragraph 5.5).
I hope it would help you.
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