在使用Jquery打开之前检查一个弹出窗口是否已经打开 [英] Check if a popup window is already open before opening it using Jquery

问题描述

我想检查弹出窗口是否已经打开，然后打开弹出窗口。
如何使用Jquery完成它？

I want to check if a popup window is already open , before I open the popup window. How do I get it done using Jquery?

以下是我的代码，用于打开一个新的弹出窗口：

Below is my code to open a new popup window :

window.open("mystopchat.php?stat=1&session="+data['myid1']['session_id'][i],"win1","width=500,height=500"); 

现在，在我调用这个函数之前，我想确保这个弹出窗口尚未打开。 / p>

Now before I call this, I want to be sure that this popup window is not already open.

推荐答案

这是我使用的一个小技巧，也许您可​​以使用它：

This is a little trick I use, perhaps you could use it:

    var winRef; //This holds the reference to your page, to see later it is open or not

    function openWindow() {  
        var url = //Your URL;
        if (typeof (winRef) == 'undefined' || winRef.closed) {
            //create new, since none is open
            winRef = window.open(url, "_blank");
        }
        else {
            try {
                winRef.document; //if this throws an exception then we have no access to the child window - probably domain change so we open a new window
            }
            catch (e) {
                winRef = window.open(url, "_blank");
            }

            //IE doesn't allow focus, so I close it and open a new one
            if (navigator.appName == 'Microsoft Internet Explorer') {
                winRef.close();
                winRef = window.open(url, "_blank");
            }
            else {
                //give it focus for a better user experience
                winRef.focus();
            }
        }
    }

希望它有帮助。

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