如何从此HTML中获取数据以在SQL中进行查询？ [英] How can I get data from this HTML to query in SQL?

问题描述

这是用于发送数据的按钮

 < a href =＃myModaldata-toggle = modalid =78data-target =＃edit-modal> < button type =button> 
< i class =glyphicon glyphicon-zoom-in>< / i> 
< /按钮>< / a> 
  

此代码显示数据

 <？php echo $ er =< div class = \modal-body edit-content \>< / div>; ？> 
  

我想 $ er 在下面查询

 <？php 
 $ str =SELECT * FROM examquestion WHERE EQ_ID ='$ er'; 
 $ Recordset7 = mysql_query（$ str）或die（mysql_error（））; 
 $ row_Recordset7 = mysql_fetch_assoc（$ Recordset7）; 
 
 echo $ row_Recordset7 ['EQ_ID']; ？> 
  

脚本

 <脚本> $（'＃edit-modal'）。on（'show.bs.modal'，function（e）{
 
 var $ modal = $（this），
 Id = e.relatedTarget.id; 
 
 $ modal.find（'。edit-content'）。html（Id）; 
 
 
}）
< / script> 
  

解决方案

您可以使用AJAX来完成。
了解这些：

http：// www.w3schools.com/ajax/

http://php.net/manual/en/mysqli.quickstart.prepared-statements.php

准备好的语句将为您节省SQL注入攻击。练习使用它，特别是如果你正在做一个含有用户输入的查询。

HTML

 < a href =＃myModaldata-toggle =modalid =78class ='get-content'data-target =＃edit-modal> 
< button type =button> 
< i class =glyphicon glyphicon-zoom-in>< / i> 
< / button> 
< / a> 
< div id =edit-modal> 
< div class =modal-body edit-content>< / div> 
< / div> 
  

PHP（content.php）使用过程式mysql

 <？php 
 $ er = $ _POST ['id']; 
 $ str =SELECT * FROM examquestion WHERE EQ_ID ='$ er'; 
 $ Recordset7 = mysql_query（$ str）或die（mysql_error（））; 
 $ row_Recordset7 = mysql_fetch_assoc（$ Recordset7）; 
 
 echo $ row_Recordset7 ['EQ_ID']; 
？> 
  

PHP使用OOP mysqli（预备语句）

  $ mysqli = new mysqli（localhost，user，password，database）; 
 $ query =SELECT content FROM examquestion WHERE EQ_ID =？; 
 if（$ stmt = $ mysqli-> prepare（$ query））
 {
 $ stmt-> bind_param（s，$ er）; 
 if（$ stmt-> execute（））
 {
 $ stmt-> bind_result（$ content）; 
 while（$ stmt-> fetch（））{
 echo $ content; 
} 
} 
 $ stmt-> close（）; 
 
  

JS

 <脚本> 
 $（'a.get-content'）。click（function（）{
 var contentId = $（this）.attr（'id'）; 
 var modalId = $（this ）.attr（'data-target'）; 
 $ .ajax（{
 url：content.php，
 type：POST，
 data：{id ：contentId}，
 dataType：html，
 success：function（data）{
 $（modalId）.find（'。edit-content'）。eq（0）.html （data）; 
} 
}）; 
 
}）; 
< / script> 
  

This is the button used to send the data

  <a href="#myModal" data-toggle="modal" id="78" data-target="#edit-modal"> <button type="button"   >
    <i class="glyphicon glyphicon-zoom-in"></i>
    </button></a> 

This code shows the data

 <?php  echo  $er="<div class=\"modal-body edit-content\"></div>";  ?>

I want $er to query in below

<?php       
$str = "SELECT * FROM examquestion WHERE EQ_ID = '$er' ";
$Recordset7 = mysql_query($str) or die(mysql_error());
$row_Recordset7 = mysql_fetch_assoc($Recordset7);

echo $row_Recordset7['EQ_ID']; ?>

script

<script>
        $('#edit-modal').on('show.bs.modal', function(e) {

            var $modal = $(this),
                Id = e.relatedTarget.id;

                    $modal.find('.edit-content').html(Id);


        })
    </script>

解决方案

You can do it by using AJAX. Learn these:

http://www.w3schools.com/ajax/

http://php.net/manual/en/mysqli.quickstart.prepared-statements.php

Prepared statements will save you from SQL Injection attacks. Practice to use it specially if you're doing a query that has an input from user.

HTML

<a href="#myModal" data-toggle="modal" id="78" class='get-content' data-target="#edit-modal">
  <button type="button">
    <i class="glyphicon glyphicon-zoom-in"></i>
  </button>
</a>
<div id="edit-modal">
  <div class="modal-body edit-content"></div>
</div>

PHP (content.php) Using procedural mysql

<?php       
   $er = $_POST['id'];
   $str = "SELECT * FROM examquestion WHERE EQ_ID = '$er' ";
   $Recordset7 = mysql_query($str) or die(mysql_error());
   $row_Recordset7 = mysql_fetch_assoc($Recordset7);

   echo $row_Recordset7['EQ_ID'];  
?>

PHP Using OOP mysqli (prepared statement)

$mysqli = new mysqli("localhost", "user", "password", "database");
$query = "SELECT content FROM examquestion WHERE EQ_ID = ?";
if ( $stmt = $mysqli->prepare($query) )
{
    $stmt->bind_param("s", $er);
    if ( $stmt->execute() )
    {
       $stmt->bind_result($content);
       while ($stmt->fetch()) {
          echo $content;
       }
    }
    $stmt->close();
}

JS

<script>
        $('a.get-content').click(function() {
            var contentId = $(this).attr('id');
            var modalId = $(this).attr('data-target');
            $.ajax({
                url: "content.php",
                type: "POST",
                data: {id: contentId},
                dataType: "html",
                success:function(data){
                    $(modalId).find('.edit-content').eq(0).html(data);
                 }
            });

        });
</script>

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