只有当你点击复选框时，表单才能工作 [英] Form only working when you hit the checkbox
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问题描述
我正在制作一份表格，希望在复选框勾选或检查时能够提交表格。我没有收到任何其他错误，当我登录时没有检查这个盒子。
/sites/2a/d/dbcf5d6440/public_html/MySQL/Challenges/Secretdiary.php on line 91这是我的代码！
<？php
session_start（）;
$ error =;
if（array_key_exists（logout，$ _GET））{
unset（$ _ SESSION）;
setcookie（id，，time（） - 60 * 60）;
$ _COOKIE [id] =;
其他if（array_key_exists（id，$ _SESSION）or array_key_exists（id，$ _COOKIE））{
header（Location：loggedinpage.php ）; （XXX，XXX，XXX，XXX ，XXX）;
if（mysqli_connect_error（））{
die（数据库连接错误）;
}
if（！$ _ POST ['email']）{
$ error。=电子邮件地址是所需<峰; br>中;
}
if（！$ _ POST ['password']）{
$ error。=需要密码< br>;
if（$ error！=）{
$ error =< p>您的表单中存在错误< p>中$错误。
$ b} else {
if（$ _ POST ['signUp'] =='1'）{
$ query =SELECT id FROM 'users` WHERE email ='.mysqli_real_escape_string（$ link，$ _POST ['email']）。'LIMIT 1;
$ result = mysqli_query（$ link，$ query）;
if（mysqli_num_rows（$ result）> 0）{
$ error =该电子邮件地址已拍摄。
$ b} else {
$ query =INSERT INTO`users`（`email`，`password`）VALUES（'。mysqli_real_escape_string（$ link，$ _POST [ 'email']）。'，'.mysqli_real_escape_string（$ link，$ _POST ['password']）。'）;
if（！mysqli_query（$ link，$ query））{
$ error =< p>无法注册您，请重试< / p> ;
$ b} else {
$ query =UPDATE`users` SET password ='.md5（md5（mysqli_insert_id（$ link））。$ _ POST ['password' ]）。 'WHERE id =.mysqli_insert_id（$ link）。LIMIT 1;
mysqli_query（$ link，$ query）;
$ _SESSION ['id'] = mysqli_insert_id（$ link）;
if（$ _POST ['stayLoggedIn'] =='1'）{
setcookie（id，mysqli_insert_id（$ link），time（）+ 60 * 60 * 24 * 365）;
}
} header（Location：loggedinpage.php）;
} else {
$ query =SELECT * FROM`users` WHERE email =' .mysqli_real_escape_string（$ link，$ _POST ['email']）。';
$ result = mysqli_query（$ link，$ query）;
$ row = mysqli_fetch_array（$ result）;
if（array_key_exists（id，$ row））{
$ hashedPassword = md5（md5（$ row ['id']）。_ _ POST ['password']）;
if（$ hashedPassword == $ row ['password']）{
$ _SESSION ['id'] = $ row ['id'];
if（$ _POST ['stayLoggedIn'] =='1'）{
setcookie（id，$ row（$ link），time（）+ 60 * 60 * 24 * 365）;
}
}
}
}
}
}
？>
< div id =error><？php echo $ error; ？>< / DIV>
< form method =post>
< input type =emailname =emailplaceholder =Your Email Eg。JoBloggs@me.co.uk>
< input type =passwordname =passwordplaceholder =Password>
< input type =checkboxname =stayLoggedInvalue = 1>
< input type =hiddenname =signUpvalue =1>
< input type =submitname =submitvalue =注册！>
< / form>
< form method =post>
< input type =emailname =emailplaceholder =Your Email Eg。JoBloggs@me.co.uk>
< input type =passwordname =passwordplaceholder =Password>
< input type =checkboxname =stayLoggedInvalue = 1>
< input type =hiddenname =signUpvalue =0>
< input type =submitname =submitvalue =Log In！>
< / form>
解决方案
复选框只发送值WHE CHECKED。因此，您必须执行 isset（$ _ POST ['stayLoggedIn']）以查看是否选择了该值，否则该索引将不存在于PHP POST值中。 / p>
I am making a form and I wish for the form to be able to be submitted when the checkbox is either ticked or checked. I don't get any other errors when I login without checking the box apart from this one
Notice: Undefined index: stayLoggedIn in /home/sites/2a/d/dbcf5d6440/public_html/MySQL/Challenges/Secretdiary.php on line 91
Here is my code!
<?php
session_start();
$error="";
if (array_key_exists("logout", $_GET)) {
unset($_SESSION);
setcookie("id", "", time() - 60*60);
$_COOKIE["id"] = "";
} else if(array_key_exists("id", $_SESSION) OR array_key_exists("id", $_COOKIE)) {
header("Location: loggedinpage.php");
}
if(array_key_exists("submit", $_POST)) {
$link = mysqli_connect("XXX", "XXX", "XXX", "XXX");
if (mysqli_connect_error()) {
die("Database Connection Error");
}
if(!$_POST['email']) {
$error.= "An Email Address is required<br>";
}
if(!$_POST['password']) {
$error.= "A Password is required<br>";
}
if($error != "") {
$error = "<p>There were error(s) in your form</p>".$error;
} else {
if($_POST['signUp'] == '1' ) {
$query = "SELECT id FROM `users` WHERE email = '".mysqli_real_escape_string($link, $_POST['email'])."' LIMIT 1";
$result = mysqli_query($link, $query);
if (mysqli_num_rows($result) > 0) {
$error = "That email address is taken.";
} else {
$query = "INSERT INTO `users` (`email`, `password`) VALUES('".mysqli_real_escape_string($link, $_POST['email'])."', '".mysqli_real_escape_string($link, $_POST['password'])."')";
if (!mysqli_query($link, $query)) {
$error="<p>Could not sign you up, please try again</p>";
} else {
$query = "UPDATE `users` SET password = '".md5(md5(mysqli_insert_id($link)).$_POST['password']). "' WHERE id = ".mysqli_insert_id($link)." LIMIT 1";
mysqli_query($link, $query);
$_SESSION['id'] = mysqli_insert_id($link);
if ($_POST['stayLoggedIn'] == '1') {
setcookie("id", mysqli_insert_id($link), time() + 60*60*24*365);
}
} header("Location: loggedinpage.php");
}
} else {
$query = "SELECT * FROM `users` WHERE email = '".mysqli_real_escape_string($link, $_POST['email'])."'";
$result = mysqli_query($link, $query);
$row = mysqli_fetch_array($result);
if (array_key_exists("id", $row)) {
$hashedPassword = md5(md5($row['id']).$_POST['password']);
if ($hashedPassword == $row['password']) {
$_SESSION['id'] = $row['id'];
if ($_POST['stayLoggedIn'] == '1') {
setcookie("id", $row ($link), time() + 60*60*24*365);
}
}
}
}
}
}
?>
<div id="error"><?php echo $error; ?></div>
<form method="post">
<input type="email" name="email" placeholder="Your Email Eg. JoBloggs@me.co.uk">
<input type="password" name="password" placeholder="Password">
<input type="checkbox" name="stayLoggedIn" value=1>
<input type="hidden" name="signUp" value="1">
<input type="submit" name="submit" value="Sign Up!">
</form>
<form method="post">
<input type="email" name="email" placeholder="Your Email Eg. JoBloggs@me.co.uk">
<input type="password" name="password" placeholder="Password">
<input type="checkbox" name="stayLoggedIn" value=1>
<input type="hidden" name="signUp" value="0">
<input type="submit" name="submit" value="Log In!">
</form>
解决方案
Checkboxes only send the value WHEN CHECKED. So you have to do an isset($_POST['stayLoggedIn']) to see if the value was selected, otherwise that index will not exist in the PHP POST value.
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