如何获取提交类型按钮的id，按下按钮时（PHP + HTML） [英] How to get id of submit type button, when button is pressed (PHP + HTML)

问题描述

我想打印出我按下的按钮的ID。该ID是为表格中的每个按钮动态设置的。这是我的HTML代码：

I want to print out the id of the button I pressed. The id is set dynamically for each button in a table. This is my HTML code:

    echo '<td><center><input type="submit" id="'.$row['I_ID'].'" class="btn"
name="Add" value ="Add to cart"><center></td><tr>';

我想在这里打印按钮的ID。有建议？如果（isset（$ _ POST ['Add']））{

And I want to print the id of the button here. An suggestions? Thanks.

if (isset($_POST['Add'])) {
    $ID = $_GET['id'];
    echo $ID;
    echo '<br/>' . "* The item has been added to your cart.";
}

推荐答案

如果您不希望使用隐藏字段，您可以像这样设置提交按钮：

If you do not wish to use a hidden field, you could set your submit button like this:

<button type="submit" name="id" value="value">Submit</button>

然后你可以用 $ _ GET ['id'] 。

Then you can catch it with $_GET['id'].

您可以使用许多按钮（ type =submit） id ），并且该值将是被点击的值，或者是第一个，如果通过按回车提交表单。

You can have many buttons of type="submit" with the same name (id), and the value will be the one which was clicked, or the first one, if the form was submitted by pressing enter.

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