从查询字符串第2部分中删除值 [英] Remove a value from a querystring Part 2

问题描述

扩展我的原始问题此处：我现在想删除

例如，我想删除变量 bar1 &来自查询字符串的 bar2 。我试过了下面的代码：
$ b $ pre $ echo $ parseQueryString（http：//。$ _SERVER ['HTTP_HOST']。$ _SERVER [ 'REQUEST_URI']， BAR2， BAR1）;

但是这并不会去除这两个变量，只有 bar2
$ p
$ b


$ b

谢谢，

Matt

解决方案

你会想要一些像

的

  echo parseQueryString（parseQueryString（http：//。$ _SERVER ['HTTP_HOST']。$ _SERVER ['REQUEST_URI']，bar2），bar1） ; 
  

或者，因为我假设parseQueryString是您定义的函数，您可以更改它，一个数组参数并遍历数组。

Expanding on my original question here: I would now like to remove more than 1 variable from the querystring.

For example, I want to remove the variables bar1 & bar2 from the querystring. I have tried the following code:

echo parseQueryString("http://" . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'],"bar2","bar1");

But this doesn't remove both variables, only bar2.

Any help appreciated.

Thank you,

Matt

解决方案

You'll be wanting something like

echo parseQueryString(parseQueryString("http://" . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'],"bar2"),"bar1");

Alternatively, since I'm assuming parseQueryString is a function you defined, you can change it so it accepts an array argument and loops over the array.

这篇关于从查询字符串第2部分中删除值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！