如何将我的htaccess代码转换为php头文件 [英] How to convert my htaccess code to php header

问题描述

我的.htaccess中有这些代码行。

我的问题是这行代码在我的.htaccess中，我想把它放在我的php中。

  AddType应用程序/ xml .xml 
我想要做的就是将它转换为php标题有人知道该怎么做吗？ .rss 
 Header add Access-Control-Allow-Origin*
 Header add Access-Control-Allow-Headersorigin，x-requested-with，content-type
 Header add Access-Control-Allow-MethodsPUT，GET，POST，DELETE，OPTIONS
  

解决方案

你甚至试图自己实现它，或者阅读 http：/ /php.net/manual/en/function.header.php ？

在文件的第一个输出之前写下这些行。
应该做这项工作（虽然未经测试）：

 <？php 
 // ... 
标题（'Access-Control-Allow-Origin：*'）; 
 header（'Access-Control-Allow-Headers：origin，x-requested-with，content-type'）; 
 header（'Access-Control-Allow-Methods：PUT，GET，POST，DELETE，OPTIONS'）; 
？> 
  

I have these lines of code in my .htaccess.

My problem is is this line of code is in my .htaccess i want to put it in my php.

I want to do is convert it to php header does anyone know how to do it?

AddType application/xml .xml .rss
Header add Access-Control-Allow-Origin "*"
Header add Access-Control-Allow-Headers "origin, x-requested-with, content-type"
Header add Access-Control-Allow-Methods "PUT, GET, POST, DELETE, OPTIONS"

解决方案

Did you even try to implement that yourself or read at http://php.net/manual/en/function.header.php?

Write those lines before the first output of the file.
Should do the job (although untested):

<?php
// ...
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Headers: origin, x-requested-with, content-type');
header('Access-Control-Allow-Methods: PUT, GET, POST, DELETE, OPTIONS');
?>

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