你如何使用目录路径的PHP变量？ [英] How do you use a php variable for directory path?
问题描述
我从网址获取用户ID。
这是我目前所拥有的。我想用$ userid替换它，但我不知道如何。它不工作，我似乎无法找到正确的语法，请有人可以帮忙吗？
I am getting userid from the url. This is what I have at the moment. I want to replace the one with $userid but I don't know how. It doesn't work and I can't seem to find the right syntax, please can someone help?
function returnimages($dirname = "Photos/1")
基本上我试图用html，php创建照片幻灯片和JavaScript。在开始将PHP添加到我的代码之前，我做了一些工作。我有HTML和一个外部的JavaScript改变照片，他们淡入和退出循环。我有一个JavaScript的照片数组。现在我正在尝试将PHP添加到我的html中。我希望能够通过url获得userid，然后从中获取照片从特定路径到目录中的userid。然后，我希望能够创建一组这些照片并在我的javascript中使用它们。这里是我的PHP代码嵌入在我的HTML：
Basically I am trying to create a photo slideshow using html, php and javascript. I had something working before I started adding php into my code. I had html and an external javascript that changes the photos and they fade in and out in a loop. I have a photo array in javascript. Right now I am trying to add php to my html. I want to be able to get userid via url and then from that get the photos from a specific path to the userid in the directory. Then I am hoping to create an array of these photos and use them in my javascript. Here is my php code embedded in my html:
<?php
$user_id = $_GET['userid'];
print " Hi, $user_id ";
function returnimages($dirname = "Photos/1") { //will replace 1 with userid once something starts working
$pattern="(\.jpg$)|(\.png$)|(\.jpeg$)|(\.gif$)"; //valid image extensions
$files = array();
$curimage=0;
if($handle = opendir($dirname)) {
while(false !== ($file = readdir($handle))){
if(eregi($pattern, $file)){ //if this file is a valid image
//Output it as a JavaScript array element
echo 'galleryarray['.$curimage.']="'.$file .'";';
$curimage++;
}
}
closedir($handle);
}
return($files);
}
echo 'var galleryarray=new Array();'; //Define array in JavaScript
returnimages() //Output the array elements containing the image file names
?>
和我的javascript：
And my javascript:
$（文件）.ready（function（）{
$ (document).ready(function(){
var photodisplay =
[
$("#photo1"),
$("#photo2"),
$("#photo3"),
$("#photo4"),
$("#photo5"),
];
//photodisplay[0].hide().fadeIn(3000);
var user = new Array();
[1, 2, 3, 4, 5];
// List of images for user one
/*var userphoto = new Array();
userphoto[0] = "Photos/1/1.jpg";
userphoto[1] = "Photos/1/2.jpg";
userphoto[2] = "Photos/1/1.jpg";
userphoto[3] = "Photos/1/1.jpg";
userphoto[4] = "Photos/1/1.jpg";*/
//preloading photos
var userphoto = <? echo json_encode($galleryarray); ?>;
function preloadingPhotos() {
for (var x=0; x<5; x++)
{
photodisplay[x].attr("src", "Photos/1" + userphoto[x]);
photodisplay[x].hide();
console.log("preloaded photos");
}
displayPhoto();
}
function displayPhoto(){
photodisplay[0].fadeIn(3000);
photodisplay[0].delay(3000).fadeOut(3000, function() { //first callback func
photodisplay[1].fadeIn(3000);
photodisplay[1].delay(3000).fadeOut(3000, function() { //second callback func
photodisplay[2].fadeIn(3000);
photodisplay[2].delay(3000).fadeOut(3000, function() { //third callback func
photodisplay[3].fadeIn(3000);
photodisplay[3].delay(3000).fadeOut(3000, function() { // fourth callback func
photodisplay[4].fadeIn(3000);
photodisplay[4].delay(3000).fadeOut(3000, function() {
setTimeout(displayPhoto(), 3000);
});
});
});
});
});
}// end of function displayPhoto
window.onload = preloadingPhotos;
}）; // end ready
}); //end ready
我的网址获得用户ID：
My url to get userid:
http://example.com/code.php?user_id=1
感谢您的时间！
推荐答案
问题是你总是设置dirname而不是让函数调用它。您可以更改：
The problem is that you are always setting the dirname instead of letting calling the function set it. You could change:
function returnimages($dirname = "Photos/1") {
至
function returnimages($dirname) {
因为否则 $ dirname 是总是照片/ 1 。然后，当您调用该函数时，请使用：
because otherwise the $dirname is always Photo/1. Then, when you call the function, use:
returnimages('Photos/'.$user_id);
这篇关于你如何使用目录路径的PHP变量？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
