我可以通过浏览器的HTML页面链接广播自定义意图吗？ [英] can i Broadcast custom intent through my HTML page link from browser?

问题描述

当我点击浏览器中的HTML页面链接时，我想广播自定义的意图。我知道android系统会为此播放android.intent.action.VIEW，我可以在我的应用程序中收到这个，但这样做会列出我的应用程序的每个可点击的链接，所以我想广播我的自定义意图操作。

解决方案

我已经通过以下方式解决了这个问题：

line

 < a href =intent：//example.com/test？id = 12345＃Intent; scheme = myapp ; package = com.mypackage; end>直接打开您的应用程序< / a> 
  

这里example.com/test?id=12345可以是任何你想要的东西，这将在我们的 onCreate（）方法中以我们的意图数据的形式传递，所以我给出了例如id。

scheme可以是我们需要在我们的menifest.xml中为intent-filter编写相同方案的任何字符串

软件包是您的应用软件包名称，以便将其与其他应用程序区分开来b $ b

注意：如果app没有安装在设备上，它会从AndroidMenifest中给定的有效包名称

打开google playstore .xml文件

 < intent-filter> 
 < category android：name =android.intent.category.LAUNCHER/> 
< / intent-filter> 
< intent-filter> 
  
< category android：name =android.intent.category.DEFAULT/> 
< category android：name =android.intent.category.BROWSABLE/> 
< data android：scheme =myapp/> 
< / intent-filter> 
  

您可以添加意图过滤器来执行任何我给予启动器活动的活动
注意< data android：scheme =myapp/> 方案名称必须与之前在HTML文件中给出的相同。

完成！在设备的任何浏览器中打开html文件您可以在您的活动的 onCreate（）方法中获取意图数据。

像

  Intent intent = getIntent（）; 
 if（intent！= null&& amp; intent.getData（）！= null）{
 Uri data = intent.getData（）; 
 String path = data.getPath（）; 
 String id = data.getQueryParameter（id）; 
 Log.d（ID，：+ id）; 
} 
  

I want to broadcast my custom intent when i click a link of my html page from browser. I know android system will broadcast "android.intent.action.VIEW" for this and i can receive this in my application but doing this will list my application for every clickable link so i want to broadcast my custom intent action.

解决方案

I have solved this by following

create test.html file with this single line

<a href="intent://example.com/test?id=12345#Intent;scheme=myapp;package=com.mypackage;end">Open Your Application Directly</a>

Here "example.com/test?id=12345" can be any thing you want this will be passed as intent data in our in our onCreate() method so i have given id for example.

"scheme" can be any string we need to write same scheme in our menifest.xml for intent-filter

"package" is your app package name to differentiate it from other app with same scheme

Note : If app is not installed in device then it will open google playstore from given valid package name

in AndroidMenifest.xml file

            <intent-filter>
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
            <intent-filter>
                <action android:name="android.intent.action.VIEW" />

                <category android:name="android.intent.category.DEFAULT" />
                <category android:name="android.intent.category.BROWSABLE" />
                <data android:scheme="myapp" />
            </intent-filter>

you can add intent filter for any activity i have given to launcher activity note the <data android:scheme="myapp" /> scheme name must be same as given in HTML file before.

Done! open html file in any browser of your device & click on link it will directly open your app.

You can get intent data in your activity's onCreate() method like

        Intent intent = getIntent();
        if (intent != null && intent.getData() != null) {
            Uri data = intent.getData();
            String path = data.getPath();
            String id = data.getQueryParameter("id");
            Log.d("ID", ": " + id);
        }

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