无法从服务器读取JSON响应 [英] Can't read JSON response from server

问题描述

我正在开发一些将数据发送到网站的网络应用程序。该网站将数据更新到其数据库并返回一个替换我的webapp页面的json数组。我正在使用ajax进行查询。我需要知道如何防止覆盖我的网页。服务器不是我的，所以可能有相同的原产地策略问题。

我检查了 xmlhttp.readystate 和 xmlhttp .status ，它们分别是4和0。根据stackoverflow上的一些帖子，由于起源策略，0状态发生，但我无法得到解决方案，因为通常有这个问题的人有权访问服务器端编程的变化。

I想要读取json并为我的应用程序提取值，但如果使用 xmlhttp.responseText ，服务器将返回一个空字符串。

$ p
谢谢

我的代码：

  function sendAndReceive（）{
 
 var xmlhttp; 
 xmlhttp = new XMLHttpRequest（）; 
 
 xmlhttp.onreadystatechange = function（）{
 document.getElementById（postevent）。innerHTML =state changed; 
 document.getElementById（postevent）。innerHTML =+ xmlhttp.readyState ++ xmlhttp.status; 
 if（xmlhttp.readyState == 4&& xmlhttp.status == 200）{
 document.getElementById（postevent）。innerHTML =success response; 
 document.getElementById（postevent）。innerHTML =this is it+ xmlhttp.responseText; 
} 
} 
 
 var url =http://simple.ap.ernet.in/api/home/resource.php/resource/node？; 
 url + =key =+ document.getElementById（key）。value +&; 
 url + =datasetId =+ document.getElementById（datasetId）。value +&; 
 url + =localId =+ document.getElementById（localId）。value +&; 
 url + =nodeName =+ document.getElementById（nodeName）。value +&; 
 url + =nodeDesc =+ document.getElementById（nodeDesc）。value +&; 
 url + =lat =+ document.getElementById（lat）。value +&; 
 url + =long =+ document.getElementById（long）。value; 
 
 document.getElementById（postevent）。innerHTML = url; 
 xmlhttp.open（POST，url，true）; 
 xmlhttp.send（）; 
 
  

解决方案

唯一已知的解决方法是让浏览器认为只有一个来源。最简单的方法是在您自己的服务器上放置一个代理服务器，然后中继到另一台服务器。如果您的服务器在Apache中，则可以使用 mod_proxy （请参阅此问题）。

但请注意，如果其他服务器不允许交叉源请求，则可能违反其政策。如果它是一个大型服务器，它可能会很好地检测到它并禁止你的服务器的IP。

I am working on a web app that sends some data to a website. The website updates the data to its database and returns a json array that replaces my webapp page. I am using ajax for making the query. I need to know how to prevent the overwriting of my webpage. The server is not mine so there is possibly a same origin policy problem.
I have checked the xmlhttp.readystate and xmlhttp.status, they are 4 and 0 respectively. According to some posts on stackoverflow the 0 status occurs due to the origin policy but I couldn't get a solution for this because usually the people with this problem had access to changes on the server side programming.
I want to read the json and extract values for my app but if I use the xmlhttp.responseText the server returns a blank string.

Any help is much appreciated.
Thanks

My code:

function sendAndReceive() {

    var xmlhttp;
    xmlhttp = new XMLHttpRequest();

    xmlhttp.onreadystatechange = function () {
        document.getElementById("postevent").innerHTML = "state changed";
        document.getElementById("postevent").innerHTML = "" + xmlhttp.readyState + " " + xmlhttp.status;
        if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
            document.getElementById("postevent").innerHTML = "success response";
            document.getElementById("postevent").innerHTML = "this is it" + xmlhttp.responseText;
        }
    }

    var url = "http://simple.ap.ernet.in/api/home/resource.php/resource/node?";
    url += "key=" + document.getElementById("key").value + "&";
    url += "datasetId=" + document.getElementById("datasetId").value + "&";
    url += "localId=" + document.getElementById("localId").value + "&";
    url += "nodeName=" + document.getElementById("nodeName").value + "&";
    url += "nodeDesc=" + document.getElementById("nodeDesc").value + "&";
    url += "lat=" + document.getElementById("lat").value + "&";
    url += "long=" + document.getElementById("long").value;

    document.getElementById("postevent").innerHTML = url;
    xmlhttp.open("POST", url, true);
    xmlhttp.send();
}

解决方案

The only known workaround is to let the browser think there is only one origin. The easiest is to put a proxy on your own server relaying to the other server. If your own server is in Apache, you may use mod_proxy (see this question).

But note that if the other server doesn't allow cross-origin requests, it's probably against its policy to do that. And if it's a big server, it may very well detect it and ban your server's IP.

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