取出SearchIcon的提示在搜索查看 [英] Remove the SearchIcon as hint in the searchView

问题描述

我在做一个应用程序，例如，当我点击的形象（这是一个搜索查看）

搜索垫打开！

和它看起来像

但这里的默认搜索图标（放大镜）被显示，但只要一些文本，进入此dissappears

但我不想，即使画面被点击，第一次被显示放大镜

在这里我没有使用任何XML文件

我的code是

 公共类MainActivity延伸活动{

    @燮pressLint（NewApi）
    @覆盖
    保护无效的onCreate（包savedInstanceState）{
        super.onCreate（savedInstanceState）;

        RelativeLayout的相对=新RelativeLayout的（这一点）;
        的LayoutParams PARAMS =新的LayoutParams（LayoutParams.MATCH_PARENT，LayoutParams.MATCH_PARENT）;
        relative.setLayoutParams（PARAMS）;
        的setContentView（相对）;

        搜索查看搜索查看=新的搜索查看（本）;
        traverseView（搜索查看，0）;
// searchView.setIconifiedByDefault（假）;
        的LayoutParams searchViewparams =新的LayoutParams（LayoutParams.WRAP_CONTENT，LayoutParams.WRAP_CONTENT）;
// searchViewparams.addRule（RelativeLayout.ALIGN_PARENT_RIGHT）;
        sea​​rchView.setLayoutParams（searchViewparams）;
        relative.addView（搜索查看）;
    }
    @TargetApi（Build.VERSION_ codeS.HONEYCOMB）
    @燮pressLint（NewApi）
    私人无效traverseView（查看视图，INT指数）{
        如果（查看的instanceof搜索查看）{
            搜索查看V =（搜索查看）视图;
            的for（int i = 0; I＆LT; v.getChildCount（）;我++）{
                traverseView（v.getChildAt（ⅰ），ⅰ）;
            }
        }否则，如果（查看的instanceof的LinearLayout）{
            的LinearLayout LL =（LinearLayout中）查看;
            的for（int i = 0; I＆LT; ll.getChildCount（）;我++）{
                traverseView（ll.getChildAt（ⅰ），ⅰ）;
            }
        }否则，如果（查看的instanceof的EditText）{
            （（EditText上）查看）.setTextColor（Color.GREEN）;
            （（EditText上）查看）.setHintTextColor（Color.BLACK）;
        }否则，如果（查看的instanceof的TextView）{
            （（TextView中）查看）.setTextColor（Color.BLUE）;
        }否则，如果（查看的instanceof ImageView的）{
            （（ImageView的）视图）.setImageResource（R.drawable.ic_launcher）;
        } 其他 {
            Log.v（观侦察兵，未定义视图类型在这里......）;
        }
    }
}
 

解决方案

我已经受够了这种麻烦了。我结合我发现教程和现有的应答发现这里的计算器。

  INT马吉德= getResources（）则getIdentifier（机器人：ID / search_mag_icon，NULL，NULL）;。
ImageView的magImage =（ImageView的）searchView.findViewById（马吉德）;
magImage.setLayoutParams（新LinearLayout.LayoutParams（0,0））;
 

注意到，搜索查看是一个LinearLayout中，所以使用LinearLayout.LayoutParams以避免例外。

我也试过，但它不会删除该视图。我似乎无法弄清楚原因：

  magImage.setVisibility（View.GONE）;
 

有关，你需要改变对方的观点，请参考本教程。

I am doing an application where for example when i click on the image(it is a searchView)

the search pad opens !

and it looks like

but here the default search icon (magnifier) gets displayed but this dissappears as soon as some text is entered

but i dont want that magnifier to be displayed even the image is clicked for the first time

and here i am not using any xml file

my code is

public class MainActivity extends Activity {

    @SuppressLint("NewApi")
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        RelativeLayout relative = new RelativeLayout(this);
        LayoutParams params = new LayoutParams(LayoutParams.MATCH_PARENT,LayoutParams.MATCH_PARENT);
        relative.setLayoutParams(params);
        setContentView(relative);

        SearchView searchView = new SearchView(this);
        traverseView(searchView, 0);
//      searchView.setIconifiedByDefault(false);
        LayoutParams searchViewparams = new LayoutParams(LayoutParams.WRAP_CONTENT,LayoutParams.WRAP_CONTENT);
//      searchViewparams.addRule(RelativeLayout.ALIGN_PARENT_RIGHT);
        searchView.setLayoutParams(searchViewparams);
        relative.addView(searchView);
    }
    @TargetApi(Build.VERSION_CODES.HONEYCOMB)
    @SuppressLint("NewApi")
    private void traverseView(View view, int index) {
        if (view instanceof SearchView) {
            SearchView v = (SearchView) view;
            for(int i = 0; i < v.getChildCount(); i++) {
                traverseView(v.getChildAt(i), i);
            }
        } else if (view instanceof LinearLayout) {
            LinearLayout ll = (LinearLayout) view;
            for(int i = 0; i < ll.getChildCount(); i++) {
                traverseView(ll.getChildAt(i), i);
            }
        } else if (view instanceof EditText) {
            ((EditText) view).setTextColor(Color.GREEN);
            ((EditText) view).setHintTextColor(Color.BLACK);
        } else if (view instanceof TextView) {
            ((TextView) view).setTextColor(Color.BLUE);
        } else if (view instanceof ImageView) {
            ((ImageView) view).setImageResource(R.drawable.ic_launcher);
        } else {
            Log.v("View Scout", "Undefined view type here...");
        }
    }
}

解决方案

I've had trouble with this too. I combined the tutorial I found and an existing answer found here in stackoverflow.

int magId = getResources().getIdentifier("android:id/search_mag_icon", null, null);
ImageView magImage = (ImageView) searchView.findViewById(magId);
magImage.setLayoutParams(new LinearLayout.LayoutParams(0, 0));

Take note that searchView is a LinearLayout, so use LinearLayout.LayoutParams to avoid an exception.

I also tried this but it doesn't remove the view. I can't seem to figure why.:

magImage.setVisibility(View.GONE);

For the other views that you need to change, refer to this tutorial.

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