密码保护我的Andr​​oid应用程序(简单的方法) [英] Password protecting my android app (the simple way)

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问题描述

我已经建立了我的第一个应用程序,我想密码保护它。这是为我好存储在Java文件中的密码和方法应当尽可能地简单,因为我对Java的这个程序之前没有任何经验,甚至XML。我也曾有过一些尝试,所以我一直希望有人失败可以帮助我。

我创建的布局与一个EditText字段:

 <的EditText
 机器人:ID =@ + ID / passwordedittext
 机器人:layout_width =200dp
 机器人:layout_height =50dp
 机器人:inputType =textPassword
 机器人:layout_marginTop =40dp
 机器人:layout_marginLeft =20dp>
 <不是requestFocus />
 

和一个提交按钮:

 <按钮
 机器人:ID =@ + ID /提交按钮
 机器人:layout_width =50dp
 机器人:layout_height =50dp
 机器人:layout_marginTop =40dp
 机器人:背景=@可绘制/ BGO
 机器人:可点击=真
 机器人:layout_gravity =右| center_horizo​​ntal
 机器人:layout_marginRight =20dp/>
 

Java的文件:

 包com.berry;
进口android.app.Activity;
进口android.content.Intent;
进口android.media.MediaPlayer;
进口android.os.Bundle;
进口android.view.View;
进口android.view.Window;
进口android.view.WindowManager;
进口android.widget.Button;
进口android.widget.EditText;


公共类密码延伸活动{

MediaPlayer的mpbuttonclick;


@覆盖
保护无效的onCreate(包savedInstanceState){
    super.onCreate(savedInstanceState);
    requestWindowFeature(Window.FEATURE_NO_TITLE);
    getWindow().setFlags(WindowManager.LayoutParams.FLAG_FORCE_NOT_FULLSCREEN,WindowManager.LayoutParams.FLAG_FORCE_NOT_FULLSCREEN);

    的setContentView(R.layout.password);

    mpbuttonclick = MediaPlayer.create(这一点,R.raw.key preSS);

    按钮sumbitButton =(按钮)findViewById(R.id.submitbutton);
    sumbitButton.setOnClickListener(新View.OnClickListener(){
        公共无效的onClick(视图v){
        EditText上passwordEditText =(EditText上)findViewById(R.id.passwordedittext);
                    如果(passwordEditText.getText()的toString()==MyPasswordHere){
                        startActivity(新的意向书(com.berry.intro));
                        mpbuttonclick.start();


                    }}});
    }}
 

解决方案

该部分:

 如果(passwordEditText.getText()的toString()==MyPasswordHere)
 

不正确。它应该是

 如果(passwordEditText.getText()的toString()。等于(MyPasswordHere))
 

在比较原始数据类型(如 INT 字符布尔),您可以使用 == !=
当比较对象(如字符串等),你需要使用 .equals ()方法。

参考这个网页。

I've built my first app, and I would like to password protect it. It's fine for me to store the password in the Java files and the method needs to be as simple as possible because i have no experience of java or even xml before this app. I've had a few attempts and failed so I was hoping someone can help me out.

I've created the layout with an EditText field:

<EditText
 android:id="@+id/passwordedittext"
 android:layout_width="200dp"
 android:layout_height="50dp"
 android:inputType="textPassword"
 android:layout_marginTop="40dp"
 android:layout_marginLeft="20dp">
 <requestFocus />

and a submit button:

<Button
 android:id="@+id/submitbutton"
 android:layout_width="50dp"
 android:layout_height="50dp"
 android:layout_marginTop="40dp"
 android:background="@drawable/bgo"
 android:clickable="true" 
 android:layout_gravity="right|center_horizontal" 
 android:layout_marginRight="20dp"/>

The Java file:

package com.berry;
import android.app.Activity;
import android.content.Intent;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.View;
import android.view.Window;
import android.view.WindowManager;
import android.widget.Button;
import android.widget.EditText;


public class password extends Activity{

MediaPlayer mpbuttonclick;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    requestWindowFeature(Window.FEATURE_NO_TITLE);
    getWindow().setFlags(WindowManager.LayoutParams.FLAG_FORCE_NOT_FULLSCREEN,WindowManager.LayoutParams.FLAG_FORCE_NOT_FULLSCREEN);

    setContentView(R.layout.password);

    mpbuttonclick = MediaPlayer.create(this, R.raw.keypress);

    Button sumbitButton = (Button) findViewById(R.id.submitbutton);
    sumbitButton.setOnClickListener(new View.OnClickListener() {        
        public void onClick(View v){
        EditText passwordEditText = (EditText) findViewById(R.id.passwordedittext);
                    if(passwordEditText.getText().toString()=="MyPasswordHere"){
                        startActivity(new Intent("com.berry.intro"));
                        mpbuttonclick.start();


                    }}});
    }}

解决方案

This part:

if(passwordEditText.getText().toString()=="MyPasswordHere")

is incorrect. It should be

if(passwordEditText.getText().toString().equals("MyPasswordHere"))

When comparing primitive data types (like int, char, boolean) you can use ==, !=, etc.
When comparing objects (like String, Car, etc) you need to use the .equals() method.

See also this page.

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