如何正确地将HTTP消息发送到客户端 [英] How to properly send an HTTP message to the client

问题描述

我正在使用Java的RESTful Web服务。如果出现问题，我需要一种向客户端发送错误消息的好方法。

I'm working on a RESTful web service in Java. I need a good way to send error messages to the client if something's wrong.

根据 Javadoc ， HttpServletResponse.setStatus （int status，String message）由于消息参数的含义不明确而被弃用

According to the Javadoc, HttpServletResponse.setStatus(int status, String message) is deprecated "due to ambiguous meaning of the message parameter."

是有一种设置状态消息或原因短语的首选方式响应？ sendError（int，String）方法不会这样做。

Is there a preferred way to set the status message or "reason phrase" of the response? The sendError(int, String) method doesn't do it.

编辑：
澄清，我想修改HTTP状态行，即HTTP / 1.1 404 Not Found，而不是正文内容。具体来说，我想发送回复，如HTTP / 1.1 400 Missing customerNumber参数。

To clarify, I want to modify the HTTP status line, i.e. "HTTP/1.1 404 Not Found", not the body content. Specifically, I'd like to send responses like "HTTP/1.1 400 Missing customerNumber parameter".

推荐答案

我认为任何RESTful客户端都不会期望查看原因，以找出问题所在;我见过/使用过的大多数RESTful服务都会在响应正文中发送标准状态信息和扩展消息。 sendError（int，String）非常适合这种情况。

I don't think any RESTful client would expect to look at the reason phrase to figure out what went wrong; most RESTful services I've seen/used will send the standard status info and an expanded message in the body of the response. sendError(int, String) is ideal for that situation.

这篇关于如何正确地将HTTP消息发送到客户端的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！