PHP是否具有Java的RequestDispatcher.forward的等价物？ [英] Does PHP Have an Equivalent of Java's RequestDispatcher.forward?

问题描述

在Java中，我可以编写一个非常基本的JSP index.jsp ，如下所示：

In Java I can write a really basic JSP index.jsp like so:

<％request.getRequestDispatcher（/ home.action）。forward（request，response）; ％>

这样做的结果是用户请求 index.jsp （或只是包含目录，假设 index.jsp 是目录的默认文档）将看到 home.action 浏览器重定向，即[forward]（ http://java.sun.com/javaee/5/docs/api/javax/servlet/RequestDispatcher.html#forward(javax.servlet.ServletRequest,% 20javax.servlet.ServletResponse））发生在服务器端。

The effect of this is that a user requesting index.jsp (or just the containing directory assuming index.jsp is a default document for the directory) will see home.action without a browser redirect, i.e. the [forward](http://java.sun.com/javaee/5/docs/api/javax/servlet/RequestDispatcher.html#forward(javax.servlet.ServletRequest,%20javax.servlet.ServletResponse)) happens on the server side.

我可以用PHP做类似的事吗？我怀疑可以配置Apache来处理这种情况，但由于我可能无法访问相关的Apache配置，我会对依赖于PHP的解决方案感兴趣。

Can I do something similar with PHP? I suspect it's possible to configure Apache to handle this case, but since I might not have access to the relevant Apache configuration I'd be interested in a solution that relies on PHP alone.

推荐答案

如果您担心CURL可用性，那么您可以使用 file_get_contents（）和流。设置如下函数：

If you are concerned about CURL availability then you could use file_get_contents() and streams. Setting up a function like:

function forward($location, $vars = array()) 
{
    $file ='http://'.$_SERVER['HTTP_HOST']
    .substr($_SERVER['REQUEST_URI'],0,strrpos($_SERVER['REQUEST_URI'], '/')+1)
    .$location;

    if(!empty($vars))
    {
         $file .="?".http_build_query($vars);
    }

    $response = file_get_contents($file);

    echo $response;
}

这只是设置一个GET，但你可以用<$做一个帖子c $ c> file_get_contents（）。

This just sets up a GET, but you can do a post with file_get_contents() as well.

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