jquery post返回渲染的html页面而不是sql结果 [英] jquery post returning rendered html page rather than sql result
问题描述
我在我的应用程序中使用codeigniter并且有一个完美运行的jquery post函数。
I am using codeigniter in my application and have a jquery post function that works perfectly.
$.post('getticketstacktype', {ticketnumber:ticketnumber},function(result) {
alert(result);
}
然后我在另一个编辑页面上使用完全相同的post函数。这个页面预先填充了PHP并且工作正常。
I am then using the exact same post function on another edit page. this page is prepopulated with PHP and works correctly.
我使用相同的帖子为了调用我的控制器，我检查了票号是否正确
I use the same post to call my controller, I have checked that ticketnumber value is correct
$.post('getticketstacktype', {ticketnumber:ticketnumber},function(result) {
alert(result);
}
它调用的控制器函数是：
the controller function it calls is:
function getticketstacktype(){
if (isset($_POST['ticketnumber'])){
$ticketnumber = $_POST['ticketnumber'];
$data = $this->wos_model->getticketstacktype($ticketnumber);
$this->output->set_content_type('application/json')->set_output(json_encode($data));
}
}
现在这种情况正常，结果为'7'但相反，在我的编辑页面上，它返回我呈现的整个视图页面：
所以< html>< head> ......< / html>线条徘徊）
now where this works correctly the result is '7' but instead, on my edit page it is returning my entire view page rendered:
so <html><head>......</html> hundereds of lines)
我无法弄清楚为什么我的整个页面在结束时被返回到jquery帖子另一种观点。
I cant figure out my why my entire page is being returned as a result to a jquery post when it is working in another view.
我还验证了两个观点的帖子信息与firebug相同。
I have also verified that the post information from both views is the same with firebug.
任何建议？
一如既往地谢谢。
Any advice? Thanks as always.
推荐答案
这通常发生在后端发生致命错误时。当PHP上发生致命错误时，它会构造一个页面以显示包含在框中的一些错误消息。 jQuery尝试解释为有意义的数据但它失败了。如果您在Firebug或Google Chrome Dev工具中看到此回复，您实际上可以看到该页面可以呈现。
This usually happens when a fatal error occurred in the backend. When a fatal error occurs on PHP, it constructs a page to displays some error message contained within a box. jQuery tries to interpret to a meaningful data but it fails. And if you see this response in Firebug or Google Chrome Dev tool you can actually see that the page can be rendered.
- 使用Firebug或谷歌Chrome开发工具，用于追踪从服务器发回的结果
- 确保后端没有错误
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