检查变量是否不等于多个字符串值的更简单方法？ [英] Simpler way to check if variable is not equal to multiple string values?

问题描述

当前代码：

<?php

  // See the AND operator; How do I simplify/shorten this line?
  if( $some_variable !== 'uk' && $some_variable !== 'in' ) {

    // Do something

  }

?>

并且：

<?php

  // See the OR operator; How do I simplify/shorten this line?
  if( $some_variable !== 'uk' || $some_variable !== 'in' ) {

    // Do something else

  }

?>

是否有更简单（即更短）的方式来编写这两个条件？

Is there a simpler (i.e. shorter) way to write the two conditions?

注意：是的，它们是不同的，我期待缩短代码的不同方法。

NOTE: Yes, they are different, and I am expecting different ways to shorten the codes.

推荐答案

对于您的第一个代码，您可以使用
给出的答案的简短更改@ShankarDamodaran 使用 in_array（） ：

For your first code, you can use a short alteration of the answer given by @ShankarDamodaran using in_array():

if ( !in_array($some_variable, array('uk','in'), true ) ) {

与以下内容相同：

if ( $some_variable !== 'uk' && $some_variable !== 'in' ) {

......但更短。特别是如果你比较'uk'和'in'更多。
我不使用额外的变量（ Shankar使用$ os ），而是在if语句中定义数组。有些人可能会发现它很脏，我发现它很快又整洁：D

... but shorter. Especially if you compare more than just 'uk' and 'in'. I do not use an additional variable (Shankar used $os) but instead define the array in the if statement. Some might find that dirty, i find it quick and neat :D

第二个代码的问题在于它可以很容易地用TRUE进行交换，因为：

The problem with your second code is that it can easily be exchanged with just TRUE since:

if (true) {

等于

if ( $some_variable !== 'uk' || $some_variable !== 'in' ) {

你问的是字符串的值是不是A还是不是B.如果是A，它绝对不是B，如果它是B，它肯定不是A.如果它是C或字面上的任何其他东西，它也不是A而不是B.所以该陈述总是（没有考虑到schrödingers法律）返回true。

You are asking if the value of a string is not A or Not B. If it is A, it is definitely not also B and if it is B it is definitely not A. And if it is C or literally anything else, it is also not A and not B. So that statement always (not taking into account schrödingers law here) returns true.

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