在Python中使用多个NOT IN语句 [英] Using multiple NOT IN statements with Python
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问题描述
我需要在循环中包含三个特定特定子字符串的URL。以下代码有效,但我确信有更优雅的方法:
I need to URLs with three specific specific substrings out of a loop. The following code worked, but I am sure there's a more elegant way to do it:
for node in soup.findAll('loc'):
url = node.text.encode("utf-8")
if "/store/" not in url and "/cell-phones/" not in url and "/accessories/" not in url:
objlist.loc.append(url)
else:
continue
谢谢!
推荐答案
url = node.text.encode("utf-8")
sub_strings = ['/store','/cell-phones/','accessories']
if not any(x in url for x in sub_strings):
objlist.loc.append(url)
else:
continue
来自 docs :
任何
如果iterable的任何元素为true,则返回True。如果iterable为空,则返回False。相当于:
any
returns True if any element of the iterable is true. If the iterable is empty, return False. Equivalent to:
def any(iterable):
for element in iterable:
if element:
return True
return False
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