PHP - 而/ Else错误? [英] PHP - While / Else error?
问题描述
我有以下php代码:
<?php
if (!isset($_REQUEST['search'])){
while(($write=mysql_fetch_array($gamesearched)) != null){
echo "Found!";
}else{
echo "No results";
}
}
?>
它给了我一个错误:
解析错误:语法错误,
中的意外'其他'(T_ELSE)C:\ _pp\\\\Gameplay\backgame.php在第41行
Parse error: syntax error, unexpected 'else' (T_ELSE) in C:\php\www\Gameplay\backgame.php on line 41
推荐答案
在PHP中,而
语句不能有一个 else
子句。您需要外部的东西,而
可以告诉您它是否至少执行过一次。
In PHP, a while
statement can't have an else
clause. You need something external to the while
that can tell you if it was executed at least once.
某事怎么样这样吗?
$total = mysql_num_rows($gamesearched);
if ($total > 0) {
while (($write=mysql_fetch_array($gamesearched)) !== false) {
echo "Found!";
}
} else {
echo "No results";
}
在这种情况下,我查找了之前找到的总行数我开始,但我也可以通过将计数器设置为零然后在while循环内递增来开始。这看起来像这样:
In this case, I've looked up the total number of rows found before I start, but I could also have started by setting a counter to zero and then incrementing it inside the while loop. That would look something like this:
$total = 0;
while (($write=mysql_fetch_array($gamesearched)) !== false) {
$total++;
echo "Found!";
}
if ($total == 0) {
echo "No results";
}
注意 mysql_fetch_array()
如果没有更多行,则返回 false
,所以我也为你更新了while条件。
Note that mysql_fetch_array()
returns false
if there are no more rows, so I've updated the while condition for you as well.
所有这一切,有充分的理由不在新代码中使用 mysql _ *
函数。有关更多详细信息和更好的替代方案,请参阅此问题:为什么不应该我在PHP中使用mysql_ *函数?
All that being said, there are good reasons not to use mysql_*
functions in new code. See this question for more details, and some better alternatives: Why shouldn't I use mysql_* functions in PHP?
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