怎么能“a< = b&& b< = a&& a！= b“是真实的？ [英] How can "a <= b && b <= a && a != b" be true?

问题描述

这是我必须弄清楚它是如何可能的代码。我有一个线索，但我不知道该怎么做。我认为它是负数和正数，也可能是变量修饰符。我是初学者，我到处寻找解决方案，但我找不到任何可用的东西。

Here is the code i have to figure it out how is it possible. I have a clue but i do not know how to do it. I think it is about negative and positive numbers and maybe the variable modifiers as well. I am a beginner i looked the solution everywhere but i could not find anything usable.

问题是：你需要声明并初始化这两个变量。 if条件必须为true。

the question is that: You need to declare and initialize the two variables. The if condition must be true.

代码：

if( a <= b && b <= a && a!=b){
       System.out.println("anything...");
}

感谢您抽出宝贵时间。

I appreciate you taking the time.

推荐答案

原始类型无法做到这一点。你可以用盒装整数实现它：

This is not possible with primitive types. You can achieve it with boxed Integers:

Integer a = new Integer(1);
Integer b = new Integer(1);

< = 和> = 比较将使用未装箱的值1，而！= 将比较参考并将成功，因为它们是不同的对象。

The <= and >= comparisons will use the unboxed value 1, while the != will compare the references and will succeed since they are different objects.

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