无法通过不合逻辑的线pep8错误 [英] Can't get past illogical line pep8 error

问题描述

我一直试图解决这个问题一段时间，我只是无法让它通过pep8。
这是我的代码：

I've been trying to fix this for a while now and i just can't get it to pass pep8. Here is my code:

1。

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and 
    sum(regex.count(char) for char in splitter) == 1 and 
    regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

2。

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and 
    sum(regex.count(char) for char in splitter) == 1 and 
    regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

3。

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' 
    and regex.count('(') > 1):

    print('hi')

我每次收到以下PEP8错误3 if语句：

I get the following PEP8 error on each of the 3 if statements:

E125 continuation line does not distinguish itself from next logical line

任何关于它有什么问题的想法？这些行用第一个括号缩进，所以我真的没有线索。

Any idea on what's wrong with it? The lines are indented with the first bracket so i really don't have a clue.

推荐答案

1。

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and
        sum(regex.count(char) for char in splitter) == 1 and
        regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

2。

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')' and
        sum(regex.count(char) for char in splitter) == 1 and
        regex.count('(') == 1 and regex.count(')') == 1):

    print('hi')

3。

if (len(regex) > 2 and regex[0] == '(' and regex[-1] == ')'
        and regex.count('(') > 1):

    print('hi')

这篇关于无法通过不合逻辑的线pep8错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！