调整图像大小而不失真OpenCV [英] Resize an image without distortion OpenCV
问题描述
我使用的是python 3和最新版本的openCV。我试图使用提供的调整大小功能调整图像大小,但调整大小后图像非常扭曲。代码:
I am using python 3 and latest version of openCV. I am trying to resize an image using the resize function provided but after resizing the image is very distorted. Code :
import cv2
file = "/home/tanmay/Desktop/test_image.png"
img = cv2.imread(file , 0)
print(img.shape)
cv2.imshow('img' , img)
k = cv2.waitKey(0)
if k == 27:
cv2.destroyWindow('img')
resize_img = cv2.resize(img , (28 , 28))
cv2.imshow('img' , resize_img)
x = cv2.waitKey(0)
if x == 27:
cv2.destroyWindow('img')
原始图像为480 x 640(RGB因此我通过0使其达到灰度)
The original image is 480 x 640 (RGB therefore i passed the 0 to get it to grayscale)
有没有办法我可以使用OpenCV或任何其他库来调整大小并避免失真吗?我打算制作一个手写数字识别器,我使用MNIST数据训练我的神经网络,因此我需要图像为28x28。
Is there any way i could resize it and avoid the distortion using OpenCV or any other library perhaps? I intend to make a handwritten digit recogniser and i have trained my neural network using the MNIST data therefore i need the image to be 28x28.
推荐答案
您可以尝试以下。该函数将保持原始图像的宽高比。
You may try below. The function will keep the aspect rate of the original image.
def image_resize(image, width = None, height = None, inter = cv2.INTER_AREA):
# initialize the dimensions of the image to be resized and
# grab the image size
dim = None
(h, w) = image.shape[:2]
# if both the width and height are None, then return the
# original image
if width is None and height is None:
return image
# check to see if the width is None
if width is None:
# calculate the ratio of the height and construct the
# dimensions
r = height / float(h)
dim = (int(w * r), height)
# otherwise, the height is None
else:
# calculate the ratio of the width and construct the
# dimensions
r = width / float(w)
dim = (width, int(h * r))
# resize the image
resized = cv2.resize(image, dim, interpolation = inter)
# return the resized image
return resized
以下是一个示例用法。
image = image_resize(image, height = 800)
希望这会有所帮助。
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