什么是可空＆LT的内存占用; T＆GT; [英] What is the memory footprint of a Nullable<T>

问题描述

这是 INT （的Int32 ）的4字节的内存占用。但是，什么是内存占用：

An int (Int32) has a memory footprint of 4 bytes. But what is the memory footprint of:

int? i = null;

和

int? i = 3;

这是一般或类型依赖？

Is this in general or type dependent?

推荐答案

我不是100％肯定，但我相信它应该是8个字节，4个字节为INT32，和（因为每一件事物都有为4-字节32位机器上对齐）的4个字节为一个布尔值，指示整数值是否已经被指定与否。

I'm not 100% sure, but I believe it should be 8 Bytes, 4 bytes for the int32, and (since every thing has to be 4-Byte aligned on a 32 bit machine) 4 bytes for a boolean indicating whether the integer value has been specified or not.

在一个64位的机器仍然会是8字节（64位），因为这是内存的最小块，也可以得到解决......

On a 64 Bit machine it would still be 8 bytes (64 bits) since that is the smallest chunk of memory that can be addressed...

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