IMAGEMAGICK：标签包含空白时填写 [英] IMAGEMAGICK: Filling when label contains blanks

问题描述

我使用imagemagick使用Dymo字体创建一些简单的图形。下面是一个例子：

I am using imagemagick to create some simple graphics using the Dymo font. Here is an example:

convert -background White -fill DarkRed -font Dymo -pointsize 72 label:"DYMO FONT" -trim name.png

此命令创建一个如下所示的文件：

This command creates a file that looks like this:

我希望红色一直填满，以便图像看起来像一个单一的标签。我计划在黑色背景的页面上使用它，这使它看起来更糟。

I would like the red to fill all the way across, so that the image looks like a single label. I plan to use this on a page with a black background, which makes it look even worse.

我玩了一段时间没有运气。我们将不胜感激。

I have played around with this for a while with no luck. Help would be appreciated.

版本：ImageMagick 6.9.2-7 Q16 x86_64 2015-12-06

Version: ImageMagick 6.9.2-7 Q16 x86_64 2015-12-06

O / S：Fedora 23

O/S: Fedora 23

推荐答案

我不知道为什么会这样做，但你可以生成你想要的文本用UTF不间断空格替换空格并将其发送到转换的 stdin 并询问 -label 从file中读取其文本 stdin ：

I don't know why it does that, but you can generate the text you want by replacing the space with a UTF non-breaking space and sending that to the stdin of convert and asking -label to read its text from the "file" called stdin:

printf "DYMO\xc2\xa0FONT" | 
   convert -background white -fill DarkRed -font DYMO -pointsize 72 label:@- result.png

在输出之前添加 -trim 文件名，如果你想要从边缘修剪掉多余的空白区域。

Add -trim just before the output filename if you want the extraneous white space trimmed off from around the edges.

如果你有更复杂的文字并且不想对所有空间都这样做，你可以使用一小段 Perl 或 sed 替换空格为你做...

If you had more complicated text and didn't want to do that for all spaces, you could replace spaces using a short piece of Perl or sed to do it for you...

echo -n "Text with lots of spaces." | sed 's/ /\xC2\xA0/g' | convert -background white -fill DarkRed -font dymo -pointsize 72 label:@- -trim label.png

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