如何将PHP包含定义为字符串？ [英] How do you define a PHP include as a string?

问题描述

我试过了：

$test = include 'test.php';

但通常只包含文件

推荐答案

您需要查看输出缓冲函数。

You'll want to look at the output buffering functions.

//get anything that's in the output buffer, and empty the buffer
$oldContent = ob_get_clean();

//start buffering again
ob_start();

//include file, capturing output into the output buffer
include "test.php";

//get current output buffer (output from test.php)
$myContent = ob_get_clean();

//start output buffering again.
ob_start();

//put the old contents of the output buffer back
echo $oldContent;

编辑：

正如Jeremy指出的那样，输出缓冲区堆栈。所以理论上你可以这样做：

As Jeremy points out, output buffers stack. So you could theoretically just do something like:

<?PHP
function return_output($file){
    ob_start();
    include $file;
    return ob_get_clean();
}
$content = return_output('some/file.php');

这应该等同于我更详细的原始解决方案。

This should be equivalent to my more verbose original solution.

但我没有费心去测试这个。

But I haven't bothered to test this one.

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