如何包含一个PHP，然后删除它？ [英] How to include a php and then remove it?

问题描述

好吧，我不知道这篇文章是否有正确的标题。随意改变它。

Well, I don't know if this post have the correct title. Feel free to change it.

好的，这是我的情景：

pluginA.php

function info(){
   return "Plugin A";
}

pluginB.php

function info(){
   return "Plugin B";
}

最后，我有一个插件管理器，负责导入所有插件信息池数组：

Manager.php

Finally, I have a plugin manager that is in charge of import all plugins info to pool array:
Manager.php

class Manager
{
    protected $pool;

    public function loadPluginsInfo()
    {
        $plugin_names = array("pluginA.php", "pluginB.php");

        foreach ($plugin_names as $name) 
        {
            include_once $name;
            $this->pool[] = info(); 
        }
    }
}

这里的问题是我打印池数组它只显示加载的第一个插件的信息。我认为文件包含覆盖了信息，因为它仍然从第一个包含调用info（）方法。

The problem here is that when I print pool array it only show me the info on the first plugin loaded. I supposed that the file inclusing override the info because it still calling the info() method from the first include.

有没有办法包含两个插件的信息所有插件文件的名称相同的info（）函数？

Is there a way to include the info of both plugins having the info() function with the same name for all plugins files?

提前谢谢

PS：致命的不能重新声明错误永远不会被抛出

PS: a fatal cannot redeclare error is never hurled

推荐答案

你可以用动态方式创建插件类

you can use the dynamic way to create plugin classes

插件类

class PluginA
{
    public function info()
    {
        return 'info'; //the plugin info
    }
}

经理类

class Manager
{
    protected $pool;

    public function loadPluginsInfo()
    {
        $plugin_names = array("pluginA", "pluginB"); //Plugin names

        foreach ($plugin_names as $name) 
        {
            $file = $name . '.php';
            if(file_exists($file))
            {
                require_once($file); //please use require_once
                $class = new $name(/* parameters ... */); //create new plugin object

                //now you can call the info method like: $class->info();
            }                
        }
    }
}

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