在任何应用程序弹出窗口 [英] Popup window in any app

问题描述

我想弹出在特定时间对话框中的任何应用程序，我的code：

i want to Popup dialog at a specific time in any app my code :

 public class testPOPDialog extends Activity {
/** Called when the activity is first created. */
private Handler mHandler = new Handler();
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);


    mHandler.postDelayed(mUpdateTimeTask, 1000);



}
private Runnable mUpdateTimeTask = new Runnable() {
       public void run() {
           AlertDialog d = new AlertDialog.Builder(testPOPDialog.this)
            .setTitle("tanchulai")
            .setMessage("bucuo de tanchulai")

            .create();

        d.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT);
        d.show();     
       }
    };

}

它给我

12-03 10:12:18.162: ERROR/AndroidRuntime(571): android.view.WindowManager$BadTokenException: Unable to add window android.view.ViewRoot$W@43dd71c0 -- permission denied for this window type

这是什么权限 如果我删除 d.getWindow（）的setType（WindowManager.LayoutParams.TYPE_SYSTEM_ALERT）; 我的应用程序是正确的......

what is this permission if i delete d.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT); my app is correct.....

推荐答案

将此权限您的清单：

android.permission.SYSTEM_ALERT_WINDOW

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